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Viefleur [7K]
3 years ago
7

Factor completely: 5t^2+28t+32

Mathematics
1 answer:
ira [324]3 years ago
7 0
33t^2=32
sorry if its wrong

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A silver dollar is flipped twice. Calculate the probability of each of the following occurring: a head on the first flip a tail
Amiraneli [1.4K]

Answer:

Explained below.

Step-by-step explanation:

The sample space for flipping a dollar twice is:

S = {HH, HT, TH, TT}

n (S) = 4

Independent events are those events that does not affect each other.

In this case, the outcomes of the two tosses are independent, i.e. the outcome of the second toss does not depends on the second toss.

(1)

Compute the probability of a head on the first flip:

The favorable outcomes are:

H₁ = {HH, HT}

n (H₁) = 2

P(H_{1})=\frac{n(H_{1})}{n(S)}=\frac{2}{4}=\frac{1}{2}=0.50

(2)

Compute the probability of a tail on the second flip given that the first toss was a head:

The favorable outcomes are:

T₂ | H₁ = {HT}

n (T₂ | H₁) = 1

P(T_{2}|H_{1})=\frac{n(T_{2}|H_{1})}{n(H_{1})}=\frac{1}{2}=0.50

(3)

Compute the probability of two tails:

T₁ and T₂ = {TT}

n (T₁ and T₂) = 1

P(T_{1}\cap T_{2})=\frac{n(T_{1}\cap T_{2})}{n(S)}=\frac{1}{4}=0.25

(4)

Compute the probability of a tail on the first and a head on the second:

T₁ and H₂ = {TH}

n (T₁ and H₂) = 1

P(T_{1}\cap H_{2})=\frac{n(T_{1}\cap H_{2})}{n(S)}=\frac{1}{4}=0.25

(5)

Compute the probability of at least one head on the two flips:

s = {HH, HT, TH}

n (s) = 3

P(s)=\frac{n(s)}{n(S)}=\frac{3}{4}=0.75

4 0
3 years ago
What is the solution to the equation 4 x minus 6 = 10 x minus 3?
Nadya [2.5K]

Answer:

x=-1/2

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
A lie detector is known to be 4/5 reliable when the person is guilty and 9/10 reliable when the person is innocent. If a suspect
shtirl [24]

Answer:

0.0748 = 7.48% probability that he is guilty

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Tests indicates guilty

Event B: Person is guilty

Probability that the test indicates that the person is guilty:

4/5 = 0.8 of 1/100 = 0.01(person is guilty)

1 - 0.9 = 0.1 of 1 - 0.99(person is not guilty). So

P(A) = 0.8*0.01 + 0.1*0.99 = 0.107

Test indicates guilty and the person is guilty;

0.01 of 0.8. So

P(A \cap B) = 0.01*0.8 = 0.008

What is the probability that he is guilty?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.008}{0.107} = 0.0748

0.0748 = 7.48% probability that he is guilty

8 0
3 years ago
Question 20 (5 points)
Advocard [28]

Answer:

D.) V:x=1;H:y=6

Step-by-step explanation:

The vertical intersection of the point is found by the x value. Starting at the point, move down to find the value of x. The vertical line, value x, is 1.

The horizontal intersection of point B is found by the y value. Start at the given point and move to the left to find the y value. The horizontal line, y, is 6.

(vertical,horizontal)\\\\(x,y)\\\\(1,6)

:Done

6 0
3 years ago
HELPPPP!!!! PLZ HURRY AND SHOW UR WORK!!!!
mars1129 [50]
The scale factor is 0.75 or 3/4
TR/EZ=9/12=3/4
8 0
3 years ago
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