Question

By what percent will a fraction change if its numerator is increased by 60% and its denominator is decreased by 20%?

Answer 1

N/D --> 0.8N/0.4D = 2N/D

--> 100% increase
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It's 100%, = 1 time larger, 2 times as large.

Answer 2

Answer:

It is increased by 100%. The numerator is two times more than the denominator. That's why original fraction will become $\frac{2x}{y}$.        

Step-by-step explanation:

We need to find the percentage, if its numerator is increases by 60% and its denominator decreases by 20%.

First, we let the original fraction: $\frac{x}{y}$

We have given its numerator is increases by 60% and denominator is decreases by 20% then,

New fraction will become = $\frac{1.6x}{0.8y}$.

Divide the new fraction by original fraction, then we get:

$\frac{1.6x}{0.8y}$/ $\frac{x}{y}$

$\frac{1.6x}{0.8y}$* $\frac{x}{y}$

Then, it will become $\frac{1.6}{0.8}$.

We can see that, The numerator is two times more than the denominator. That's why original fraction will become $\frac{2x}{y}$.

It is increased by 100%.

If we take an example, Suppose the original fraction is $\frac{5}{8}$ and the new fraction will become $\frac{1.6*5}{0.8*8}$.

= $\frac{8}{6.4}$ = $\frac{80}{64}$

= $\frac{10}{8}$, it is twice of original fraction $\frac{5}{8}$.