hey let me tell you this you just never helped me and cheating is not good so yeah treat people the way you want to be treated and I saw your answers to other people it's not good to cheat just a piece of advice
Answer:

Step-by-step explanation:
According to intermediate value theorem, if a function is continuous on an interval
, and if
is any number between
and
, then there exists a value,
, where
, such that 
In the given question,
Intermediate Value Theorem is used to show that there is a root of the given equation in the specified interval.
Here,

Put 

Put 

25(cards per month) x12(months in one year) =300 cards at the end of one whole year
Answer:
ok
Step-by-step explanation: