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kompoz [17]
3 years ago
15

Write the quadratic equation whose roots are −3 and 6, and whose leading coefficient is 2

Mathematics
1 answer:
enyata [817]3 years ago
5 0
X² - Sx + P = 0
x² - (-3+2)x + (-3)*2 = 0
x² - (-1)x - 6 = 0
x² + x - 6 = 0
a = 2
2x² + 2x - 12 = 0
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The proof ABC ≅ DCB that is shown.
Schach [20]

The <em><u>correct answer</u></em> is:

AAS

Explanation:

AAS stands for "angle-angle-side."  This states that if two angles and a non-included side of one triangle are congruent to the corresponding two angles and non-included side of another triangle, then the triangles are congruent.

In these triangles, we have ∠CAB ≅ ∠CDB given to us to begin with.  Throughout the proof, we find that ∠ABC ≅ ∠DCB.  We also have that CB is congruent to itself.  This is two angles and a side not included, so this is AAS.

4 0
3 years ago
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What is the result when x4 + 9x^3 - 20x2 + 14x – 14 is divided by x – 1? If
Leno4ka [110]
This was done from using the method of synthetic division. I attached the image. Hope this helps

5 0
3 years ago
I really need help! This is last minute and its 1 am. I'm tired so I'm going to leave it to you guys to solve my problems and pr
Illusion [34]

Answer:

<h2><u>question 1</u></h2>

n^{2} - 20n -96 = 0

use product and sum method

product = -96

sum = -20

numbers needed = ( -24 , 4)

n - 24 = 0

n + 4 = 0

hence <u>n = 24 and n = -4 </u>

<u></u>

<h2><u>Question 2 </u></h2>

<u />x^{2} + 12 x = 48<u />

in the form ax^{2}  +bx +c = 0

= x^{2} +12x - 48

make use of the formula :

\frac{-b+-\sqrt{b^{2} -4ac} }{2a}

replace values to make 2 equations :

1.\frac{-12+\sqrt{12^{2} -4*1*-48} }{2*1} = 3.17

2.\frac{-12-\sqrt{12^{2} -4*1*-48} }{2*1} = -15.2

hence <u>x = 3.17 and x = -15.2</u>

<u />

<h2><u>Question 3 </u></h2>

<u />x^{2} -14x+40=0<u />

use product and sum method

product = 40

sum = -14

numbers needed = (-10 , -4)

x - 10 = 0

x - 4 = 0

hence<u> x = 10 and x = 4</u>

<u />

<h2><u>Question 4 </u></h2>

<u />5b^{2} -20b-18 = 7<u />

in the form ax^{2}  +bx +c = 0

this becomes 5b^{2} -20b-18-7

= 5b^{2} -20b-25

can simplify by 5

= b^{2} -4b-5 =0\\

use product and sum method

product = -5

sum = -4

numbers needed (-5 , 1)

b-5 = 0

b + 1 = 0

hence <u>b = 5 and b = -1</u>

5 0
4 years ago
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Please solve each equation &amp; check your solution. Thank You!
Deffense [45]

Answer:

G). 1.2x + 7.92 -3.3x = 41

-2.1x=33.08

x = 33.08/-2.1

x = - 15.752

H). 3x/2 + 9/5 = 12

Multiply through by 10

15x + 18 =120

15x =120-18

15x = 102

x =102/15

x=34/5

I). 5 = 9/4 - r/3

Multiply through by 12

60= 27 - 4r

60 - 27 = -4r

33 = - 4r

r = -33/4

J). 2(x - 2) = 12

2x - 4 = 12

2x = 16

x = 16/2

x = 8

8 0
3 years ago
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sergey [27]

Answer:

The answer is 2/5

Step-by-step explanation:

10/15 simplified is 2/5

5 0
3 years ago
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