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xxMikexx [17]
2 years ago
5

PLEASE ASAP

Mathematics
2 answers:
aalyn [17]2 years ago
5 0

Answer:

R=5

Step-by-step explanation:

The area of a semi circle is 1/2(pi×R^2).

Since the area is given you would just work backwards.

Using 3.14 as "pi", you would have

39.25 = 1/2(3.14×R^2)

39.25*2 = 3.14*R^2

78.5 = 3.14* R^2

78.5/3.14 = R^2

25 = R^2

Then you would take the sqrt of R and 25

And the answer would come to 5 = R

R= radius

kvv77 [185]2 years ago
3 0
<h2>Answer -:</h2><h3>Given :</h3>
  • Area of a semicircle = 39.25
<h3>Find :</h3>
  • Radius of the semicircle
<h3>Solution :</h3>

\small \tt{Area  \: of \:  a  \: semicircle =  \frac{1}{2} \times \pi {r}^{2}  }

\small\tt{39.25 =  \frac{1}{2} \times 3.14 \times  {r}^{2}  }

\small\tt{39.25 \times 2 = 3.14 \times  {r}^{2} }

\small\tt{78.5 \:  = 3.14 \times  {r}^{2} }

\small\tt{ \frac{78.5}{3.14} =  {r}^{2} }

\small\tt{ {r }^{2}  = 25}

\small\tt{r =  \sqrt{25} = 5 }

\small\tt{r = 5}

<h3>Radius = 5</h3>

Hope it will help you

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The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
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Answer:

Demand Equation: q = 15125 - 25p.

Supply Equation: 80p - 24000 = 9q.

Equilibrium Price: $525.

Equilibrium Quantity: 2000 units.

Step-by-step explanation:

To solve this question, first, the demand equation has to be calculated. Let price be on the y-axis and quantity by on the x-axis. It is given that p = $485 when q = 3000 units. This can also be written as (q₁, p₁) = (3000, 485). It is also given that when the price goes down by $20, the quantity increases by 500 units. Therefore, (q₂, p₂) = (3500, 465). Due to the statement "For each decrease in unit price of $20 below $485, the quantity demanded increases by 500 units", the demand function will be linear i.e. a straight line. This is because the word "for each" has been used. Therefore, finding the equation of the demand function:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 485)/(q - 3000) = (465 - 485)/(3500 - 3000).

(p - 485)/(q - 3000) = (-20)/(500).

(p - 485)/(q - 3000) = -1/25.

25*(p - 485) = -1*(q - 3000).

25p - 12125 = -q + 3000.

25p + q = 15125.

q = 15125 - 25p. (Demand Equation).

Second, find the supply equation. It is given that the suppliers will not sell the product below or at the price of $300. Therefore, (q₁, p₁) = (0, 300). Also, the suppliers will sell 2000 units if the price is $525. Therefore, (q₂, p₂) = (2000, 525). Since it is mentioned that supply equation is linear, therefore:

(p - p₁)/(q - q₁) = (q₂ - q₁)/(p₂ - p₁).

(p - 300)/(q - 0) = (525 - 300)/(2000 - 0).

(p - 300)/(q) = (225)/(2000).

(p - 300)/(q) = 9/80.

80*(p - 300) = 9*(q).

80p - 24000 = 9q. (Supply Equation).

Equilibrium exists when demand = supply. This means that the demand and the supply equations have to be solved simultaneously. Therefore, put demand equation in supply equation:

80p - 24000 = 9(15125 - 25p).

80p - 24000 = 136125 - 225p.

305p = 160125.

p = $525.

Put p = $525 in demand equation:

q = 15125 - 25p.

q = 15125 - 25(525).

q = 15125 - 13125.

q = 2000 units.

To summarize:

Demand Equation: q = 15125 - 25p!!!

Supply Equation: 80p - 24000 = 9q!!!

Equilibrium Price: $525!!!

Equilibrium Quantity: 2000 units!!!

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