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The given measurement of the Instagram photo is "4" by "4". And a poster enlargement is being printed with a scale factor of 8.5 .
So on using the scale factor of 8.5 , lengths of new sides are "8.5 *4" by "8.5 *4"
= " 34" by "34" .
So the new lengths of the enlarged pictures are of dimension "34" by "34" .
Answer:
b. w= 8x^2-2y / y
Step-by-step explanation:
Given:
(2*x^2)/y = (w+2)/4
Isolating w, we get:
w = (8*x^2)/y - 2
Multiplying and dividing the second term in the right-side of the equality by y, we get:
w = (8*x^2)/y - 2*y/y
Subtracting the fractions:
w = (8*x^2 - 2y)/y
Answer:
-54
Step-by-step explanation:
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
