Answer:
2x-3/y-5/37=0
Step-by-step explanation:
here, given equation of line is
y=3/2x+3
or,y(2x+3)=3
or,2x+3=3/y
or,2x-3/y+3=0...eqn(i)
equation of any line parallel to line (i) is
2x-3/y+k=0.. eqn(ii)
since, the line passes through (4,5)[replacing x=4 and y=5 in eqn(ii), we get]
2*4-3/5+k=0
or,8-3/5+k=0
or,40-3/5+k=0
or,k=-5/37
substituting the value of k=-5/37 in eqn(ii)
2x-3/y-5/37=0 is the required equation of line.
Answer:
349800
4
Step-by-step explanation:
First Part:
The question tells you to multiply by 10 to the power of 4.
This implies that you can move the decimal point 4 numbers to the right
When you move the decimal two numbers to the right you get 3498
Then you got to move it two more numbers to the right
3498 can also be written as 3498.0000000000 (infinite amount of zeros)
So moving the decimal two more places you get 349800
Second Part:
10^4 = 10 * 10 * 10 * 10
= 10000
Count the zeros you get 4.
Answer:
Hey there!
Consecutive integers mean that the numbers are next to each other.
Consecutive even integers mean that the numbers are separated by a number between them.
Thus, if x is the smaller number, x+2 can be used to write the larger number.
x+x+2=1594
2x+2=1594
2x=1592
x=796.
The two numbers are 796 and 798.
Let me know if this helps :)