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Soloha48 [4]
4 years ago
5

Jeannine runs for 45 minutes every day for exercise. it takes her 8 minutes to run a mile, and she spends 5 minutes stretching h

alfway through the run. if x represents the number of miles she runs, then 8x 5 ≤ 45 represents the time she runs each day. what is the fewest number of miles jeannine must run to complete her daily exercise
Mathematics
1 answer:
ki77a [65]4 years ago
6 0
8x5<45         So the fewest of miles she could run is 1, 2, 3, or 4 miles
   -5  -5
    ------
     8x<40
     -------
      8   8
x<5
  --                           
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Solve for y: 3d = 7y + 5
pogonyaev

Answer:

d = \frac{7y+5}{3}

Step by step explanation:

3d = 7y+5

<em>Divide both sides by 3</em>

<em />\frac{3d}{3}<em>= </em>\frac{7y}{3}+ \frac{5}{3}

<em>Simplify</em>

\frac{7y+5}{3}

7 0
3 years ago
A concession stand at an athletic event is trying to determine how much to sell cola and iced tea for in order to maximize reven
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Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y)  = $100x-34x^2+5xy+50y+3xy-16y^2$

$R(x,y) = 100x-34x^2+8xy+50y-16y^2$

In order to maximize the revenue, set

$R_x=0, \ \ \ R_y=0$

$R_x=\frac{dR }{dx} = 100-68x+8y$

$R_x=0$

$68x-8y=100$  .............(i)

$R_y=\frac{dR }{dx} = 50-32x+8y$

$R_y=0$

$8x-32y=-50$  .............(ii)

Solving (i) and (ii),

4 x (i)    ⇒       272x - 32y = 400

     (ii)   ⇒   (-<u>)     8x - 32y = -50   </u>

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∴   $x=\frac{450}{264}=\frac{75}{44}$

     $y=\frac{175}{88}$

So, x ≈  $ 1.70      and    y = $ 1.99

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Thus, 1.70 dollars per cola

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Maximum revenue = $ 134.94

4 0
3 years ago
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Answer:

d

Step-by-step explanation:

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a

x² - 1

= x² - 1²

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b

x² - y²

= (x - y)(x + y)

c

x² - 4

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= (x - 2)(x + 2)

d

4 - 16y ← 16y is not a perfect square and so cannot be factored

If it was 4 - 16y² then it could be factored using difference of squares

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