X+y+z=92
y=3x
z=2x-10
subsitute
x+3x+2x-10=92
6x-10=92
add 10 to both sdies
6x=102
divide by 6
x=17
subsitute
y=3x
y=3(17)
y=51
z=2x-10
z=2(17)-10
z=34-10
z=24
x=17
y=51
z=24
the numbers are 17,51,24
17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
I am big pp lol xD hxyjdrh
<span> y = |x-2|+4
it is a negative 2 because you do the inverse</span>
X = el entero más pequeño
Entonces, el otro entero = x+1
Y podemos poner estos numeros en la equacion dado:
x + x+ 1 = 25
2x + 1 = 25
2x = 24
x = 12
x+ 1 = 13
Entonces, los enteros son 12 & 13.
