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Oksanka [162]
3 years ago
6

Write an expression that is equivalent to (5z+ 16). (4 points)

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0
<u><em>The correct expression given is:</em></u>
\frac{3}{4} (5z + 16)

<u><em>Answer:</em></u>
option D is the correct one

<u><em>Explanation:</em></u>
<u>We will start by simplifying the given expression as follows:</u>
\frac{3}{4} (5z + 16)

<u>We will use the distributive property to get rid of the brackets as follows:</u>
\frac{3}{4} * 5z +  \frac{3}{4} * 16

<u>We will now compute the multiplication, this will give us:</u>
\frac{3*5z}{4} +  \frac{3*16}{4}  \\  \frac{15z}{4} + 12

<u>This is the simplest form of our expression.</u>
Comparing this with the choices, we will find that the <u>correct choice is D</u>

Hope this helps :)
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Step-by-step explanation:

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3 years ago
Willy Wonka has 2 candies, Wonka bars and Everlasting Gobstoppers. Both have both natural sugar and sucrose in them. Each Wonka
love history [14]

Answer:

Wonka bars=3 and  Everlasting Gobstoppers=24

Step-by-step explanation:

let the wonka bars be X

and everlasting gobstoppers be Y

the objective is to

maximize 1.3x+3.2y=P

subject to constraints

natural sugar

4x+2y=60------1

sucrose

x+3y=75---------2

x>0, y>0

solving 1 and 2 simultaneously we have

4x+2y=60----1

x+3y=75------2

multiply equation 2 by 4 and equation 1 by 1 to eliminate x we have

 4x+2y=60

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-0-10y=-240

10y=240

y=240/10

y=24

put y=24 in equation 2 we have'

x+3y=75

x+3(24)=75

x+72=75

x=75-72

x=3

put x=3 and y=24 in the objective function we have

maximize 1.3x+3.2y=P

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3.9+76.8=P

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P=$80.9

8 0
4 years ago
Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti
julsineya [31]

Answer:

see below

Step-by-step explanation:

Dosage= 500 mg

Frequency= twice a day (every 12 hours)

Duration= 10 days

Number of dosage= 10*2= 20

residual drug amount after each dosage= 4.5%

We can build an equation to calculate residual drug amount:

d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage

After first dose residual drug amount is:

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After second dose:

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As per the equation, the higher the t, the greater the residual drug amount in the body.

Maximum residual drug will be in the body:

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Maximum drug will be in the body right after the last dose, when the amount will be:

  • 500+19*22.5= 927.5 mg
5 0
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