Angle AOC = 46° Find angle BPO
We have congruent right triangles PAO and PBO, right angles A and B.
So AOC=BOC=46 degrees,
PBO is a right angle so BPO is complementary to BOC, so 42 degrees
Answer: 42 degrees
Warning: This might be rough...
First draw it out. Label the angles at the corners of the triangle 60 (definition of equilateral triangles). Now draw a line from the center of the circle to the corner, splitting the corner in half. Label this line R and a corner as 30 degrees. No to find the height of this triangle, you do rsin(30). The base of this triangle is 2rcos(30). Now find the area of this mini triangle (rsin(30)*2rcos(30)/2=r/2*rsqrt(3)/2=r^2sqrt(3)/4). Now multiply this by 3 because you have 3 mini triangles... to get...
<span>r^2 3sqrt(3)/4</span>
Answer:
40
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Step-by-step explanation:
4÷1/2=8
5×8=40
Look where the line is touching on the y-axis and that will be your y-value. From there or somewhere on the line use rise over run (rise/run, do not divide). Count how many times it goes up and then count how many times it goes left or right. Make sure to look where the line is going, up or down slanted. If the line is going down, but slanted it will be a negative slope; line going up and slanted is positive.
Answer:
I think that is correct, sorry is i get it wrong
