Whatever% of anything is just (whatever/100) * anything.
x = ounces of 14% iodine.
y = ounces of 29% iodine.
we know that in a 14% iodine solution, 14% is iodine and the rest is something else, we also know that "x" ounces of the solution have 14% of iodine, how much is that? (14/100) * x, or 0.14x.
likewise, in the 89 ounces of 47% solution there is (47/100) * 89 of iodine.
and likewise as well, in "y" ounces of 29% iodine there is (29/100) * y, or 0.29y of iodine.
bearing in mind that, whatever "x" and "y" may be, x + 89 = y, and that the sum of the iodine amounts also will equate 0.29y.
Answer:
see explanation
Step-by-step explanation:
The hypotenuse is the longest side thus is (4x + 1)
The legs are 2x and (4x - 1)
Using Pythagoras' theorem, then
(4x + 1)² = (2x)² + (4x - 1)² ← expanding factors
16x² + 8x + 1 = 4x² + 16x² - 8x + 1 , that is
16x² + 8x + 1 = 20x² - 8x + 1 ( subtract 20x² - 8x + 1 from both sides )
- 4x² + 16x = 0 ( multiply through by - 1 )
4x² - 16x = 0 ← factor out 4x from each term
4x(x - 4) = 0
Equate each factor to zero and solve for x
4x = 0 ⇒ x = 0
x - 4 = 0 ⇒ x = 4
Now x > 0, thus x = 4
2x = 2(4) = 8
4x - 1 = 4(4) - 1 = 16 - 1 = 15
4x + 1 = 4(4) + 1 = 16 + 1 = 17
Thus
perimeter = 8 + 15 + 17 = 40 cm
They can not, there are only 2 sides and they probably flipped it different ways. They got 'lucky'.
Answer:
Using the table
Maria does 1/4 of the job in 1 hour since it takes her 4 hours to complete the job , she works x hours and completes x/4 of the task
Josie does 1/2 of the job in 1 hour since it takes her 2 hours to complete the job , she works x hours and completes x/2
x/4 + x/2 = 1 completed task
Multiply by 4
x/4 *4 + x/2*4 = 1*4
x+2x =4
3x=4
x = 4/3
x = 1 1/3 hours
Answer:
Mean=2.53
median=2
mode=2
range=3
Step-by-step explanation:
1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4
MEAN
Add up all data values to get the sum
Count the number of values in your data set
Divide the sum by the count
38/15=2.53
MEDIAN
Arrange data values from lowest to the highest value
The median is the data value in the middle of the set
If there are 2 data values in the middle the median is the mean of those 2 values.
MODE
Mode is the value or values in the data set that occur most frequently.
RANGE
18-15=3