Before answering these questions, we need to write out both equations.
For Job 'A', his salary would be: 55,000 + 2,500n
This assumes 'n' equals the number of years Lenny spends at these companies.
For Job 'B', his salary would be: 62,000 + 2,000n
A.
So basically we need to find a number were:
55,000 + 2,500n = 62,000 + 2,000n
is true. So basically solve ^that^ equasion.
55,000 + 2,500n = 62,000 + 2,000n
simplify
500n = 7,000
devide
n = 14
Fourteen years is your answer.
B.
a. 55,000 + 2,500n
b. 62,000 + 2,000n
So in order to answer this question, you basically just have to replace 'n' with the number '20', and see which one's bigger.
a.
55,000 + 2,500(20)
55,000 + 50,000
105,000
b.
62,000 + 2,000(20)
62,000 + 40,000
102,000
105,000 > 102,000
So your answer is:
Lenny should go to company 'a' because 105,000 is greater than 102,000.
[[tip: If you want to wow, surprise, or confuse your teacher (depending on her actual intelligence) write something like, 'another reason Lenny should choose company 'a' is because it gives higher annual raises, which is better in long-term.' He/She may not get it though, lol, wrong class.]]
Anyway, I hope this helped! :D
The only restraints on profit result from the restriction on the domain which in turn place a restriction on profit.
0≤k. Knives sold cannot be negative.
So the range of profit or p is:
p=[-500, +oo)
Profit increases as the number of knives sold increases. $200 more profit is gained by each sale of a knife.
4000=200k-500
4500=200k
k=22.5
Since k is for knives sold, it must be an integer value, so a $4000 profit is not possible. At 22, p=3900 and at 23, p=4100
Answer: 321 for #1 and 52 for #2
Step-by-step explanation: I divided and got 321 for #1 and 52 for #2.
Answer:
1st: 3*root6 + 5
2nd: 35*root2 + 115
3rd: 24*root2 - 20*root6 + 15*root3 - 18
4th: 17*root6 - 38
5th: 13*root10 - 42
Step-by-step explanation:
To simplify these expressions we need to use the distributive property:
(a + b) * (c + d) = ac + ad + bc + bd
So simplifying each expression, we have:
1st.
(2 root 2 + root 3 ) ( 2 root 3 - root 2)
= 4*root6 - 2*2 + 2*3 - root6
= 3*root6 - 4 + 9
= 3*root6 + 5
2nd.
(root 5 + 2 root 10) (3 root 5 + root 10)
= 3 * 5 + root50 + 6*root50 + 2*10
= 15 + 5*root2 + 30*root2 + 100
= 35*root2 + 115
3rd.
(4 root 6 - 3 root 3) (2 root 3 - 5)
= 8*root18 - 20*root6 - 6*3 + 15root3
= 24*root2 - 20*root6 + 15*root3 - 18
4rd.
(6 root 3 - 5 root 2 ) (2 root 2 - root 3)
= 12*root6 - 6*3 - 10*2 + 5*root6
= 17*root6 - 18 - 20
= 17*root6 - 38
5th.
(root 10 - 3 ) ( 4 - 3 root 10)
= 4*root10 - 3*10 - 12 + 9*root10
= 13*root10 - 30 - 12
= 13*root10 - 42
