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3 years ago

What is the product? Assume

Mathematics

1 answer:

morpeh [17]3 years ago

6 0

What the person said

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Match each equation with a value of x that satisfies it

Alexus [3.1K]

Answer:

(x-2)^1/4=2 ---> 18

√x^2+7=4. ---> -3

^3√1-x=-1. ---> 2

Step-by-step explanation:

just did it on plato

5 0

2 years ago

Need help with Calculus 1 inverse trig functions

lidiya [134]

Answer:

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}$

Step-by-step explanation:

<u>The Derivative of a Function</u>

The derivative of f, also known as the instantaneous rate of change, or the slope of the tangent line to the graph of f, can be computed by the definition formula

$\displaystyle f'(x)=\lim\limits_{\Delta x \rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}$

There are tables where the derivative of all known functions are provided for an easy calculation of specific functions.

The derivative of the inverse tangent is given as

$\displaystyle (tan^{-1}u)'=\frac{u'}{1+u^2}$

Where u is a function of x as provided:

$y=3tan^{-1}(x+\sqrt{1+x^2})$

If we set

$u=(x+\sqrt{1+x^2})$

Then

$\displaystyle u'=1+\frac{2x}{2\sqrt{1+x^2}}$

$\displaystyle u'=1+\frac{x}{\sqrt{1+x^2}}$

Taking the derivative of y

$y'=3[tan^{-1}(x+\sqrt{1+x^2})]'$

Using the change of variables

$\displaystyle y'=3[tan^{-1}u]'=3\frac{u'}{1+u^2}$

$\displaystyle y'=3\frac{u'}{1+u^2}=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+(x+\sqrt{1+x^2})^2}$

Operating

$\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{1+x^2+2x\sqrt{1+x^2}+1+x^2}$

$\boxed{\displaystyle y'=3\frac{1+\frac{x}{\sqrt{1+x^2}}}{2+2x^2+2x\sqrt{1+x^2}}}$

8 0

3 years ago

What is the length of the diagonal, ddd, of the rectangular prism shown below?

wel

Answer:

Step-by-step explanation:

Its 7 because khan academy and i know it

3 0

3 years ago

Read 2 more answers

What the GCF of 6 and 11

sesenic [268]

Answer:

it is 1 be ause they do not go into each other

3 0

3 years ago

Varia is studying abroad in Europe. She is required pay $3,500 (in US dollars) per year to the university, however, she must pay

sleet_krkn [62]

Answer:

213 euros per month

Step-by-step explanation:

1dollar = 0.7306euros

thus $3,500 dollars can be found by a rule of three

dollar euro

1 ⇒ 0.7306

3500 ⇒ x

we find x as follows:

$x=\frac{0.7306*3500}{1} = 2,557.1$ euros

She will pay 2,557.1 euros per year.

Dividing between the 12 months of the year:

$\frac{2,557.1}{12}=213.1$

Rounding to the nearest whole euro she will pay 213 euros per month.

7 0

3 years ago