Listen carefully to them and ask for help if you need to.
Answer:
5.71 x 10^13 C.
Explanation:
We are given the following parameters or data or information and these data are going to help us in solving this particular Question or problem effectively and efficiently;
=> mass of Earth = 5.98 × 10^ 24kg, mass of Moon = 7.35 × 10^22 kg and the radius of orbit = 3.84 × 10^8m.
Recall that H =( G × m1 × m2) / r^2. where m1 and m2 are the masses of the two bodies amd r is the radius.
We will be making use of the formula below:
the value of Q to maintain the present orbit = √ { ( 7.35 × 10^22 ) × (5.98 × 10^24) × 4 × π × V.
the value of Q to maintain the present orbit = 5.71 x 10^13 C.
Omg I wish I can but I’m struggling wit life rn
It would be helpful if I had a time period, but I'll take a shot. Double-check my answer.
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