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3 years ago

I need help solving this problem

1 answer:

4 0

Use the given values in the compound interest formula to solve for time, n.

A is the final amount of money, $2800
P is the initial or starting amount $1900
i is the interest rate as a decimal 0.025
n is time in years since it annual.

2800 = 1900(1 + 0.025)^n

2800 = 1900(1.025)^n

2800/1900 = (1.025)^n

28/19 = (1.025)^n

take the natural log of both sides to solve for exponent.

ln(28/19) = ln(1.025^n)

power rule of logarithmic moves exponent

ln(28/19) = n*ln(1.025)

ln(28/19) / ln(1.025) = n

put into a calculator

15.7 years = n

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azamat

Answer:

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Step-by-step explanation:

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3 years ago

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2 years ago

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3 years ago

Which of the following is a factor of 2x^2-3x-2

Savatey [412]

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3 years ago

Select the two values of x that are roots of this equation.

laila [671]

Answer:

x = - $\frac{5}{3}$ , x = 1

Step-by-step explanation:

Given

2x - 5 = - 3x² ( add 3x² to both sides )

3x² + 2x - 5 = 0 ← in standard form

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 5 = - 15 and sum = + 2

The factors are - 3 and + 5

Use these factors to split the x- term

3x² - 3x + 5x - 5 = 0 ( factor the first/second and third/fourth terms )

3x(x - 1) + 5(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(3x + 5) = 0 ← in factored form

Equate each factor to zero and solve for x

3x + 5 = 0 ⇒ 3x = - 5 ⇒ x = - $\frac{5}{3}$

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8 0

3 years ago