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IRINA_888 [86]
3 years ago
8

The table shows data that were collected on a hot-air balloon. Which function f(x) best models the data?

Mathematics
1 answer:
slamgirl [31]3 years ago
6 0
For the answer to the question above asking the <span>function f(x) best models the data? The f(x) models are not given but to answer this question</span> just convert the given from meter to kilometer by dividing the number by 1000. this is because 1000 meters is equal to 1 kilometers. The answer is 0.1 km
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x\cdot (-x)+7
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The answer is for the problem is 6.70
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Negative -5/8 - 1/2= <br> I wanna know fast anyone??
alexira [117]

Answer" -9/8

by-step explanation:

-5/8 - 1/2 = -9/8

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3 0
3 years ago
Suppose you invest $750.00 in a fund earning 6% simple discount. A certain time later you withdraw the investment (principal and
barxatty [35]

Answer:

4.08 + 2 = 6.08 years

Step-by-step explanation:

we know that

Simple Interest(S.I.) = (P × R × T) ÷ 100

where, P = Principal = 750

R = Rate = 6%

T = unknown

⇒ S.I. = (750 × 6 × t)÷ 100

⇒ S.I. = 45t

Also, Amount = S.I + Principal

⇒ Amount = 750 + 45t

Now Formula for Compound Interest is:

A = P(1+\frac{r}{100})^{t}

where A = Amount

=1000

P = Principle

r = rate

t = total number of year

Here, P = 750 + 45t, r = 3.5% , and t = 2.

Putting all these values in above formula:

1000 = (750 + 45t)(1+\frac{3.5}{100})^{2}

⇒ 1000 = (750 + 45t)(1.071)

⇒ t = 4.08

Hence, total time required will be 2 + 4.08 = 6.08 years.

7 0
3 years ago
Cos4theta+cos2theta/ cos4theta-cos2theta= _____
vovangra [49]

\bf \textit{Sum to Product Identities} \\\\ cos(\alpha)+cos(\beta)=2cos\left(\cfrac{\alpha+\beta}{2}\right)cos\left(\cfrac{\alpha-\beta}{2}\right) \\\\\\ cos(\alpha)-cos(\beta)=-2sin\left(\cfrac{\alpha+\beta}{2}\right)sin\left(\cfrac{\alpha-\beta}{2}\right) \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{cos(4\theta )+cos(2\theta )}{cos(4\theta )-cos(2\theta )}\implies \cfrac{2cos\left( \frac{4\theta +2\theta }{2} \right)cos\left( \frac{4\theta -2\theta }{2} \right)}{-2sin\left( \frac{4\theta +2\theta }{2} \right)sin\left( \frac{4\theta -2\theta }{2} \right)} \implies \cfrac{cos\left( \frac{6\theta }{2} \right)cos\left( \frac{2\theta }{2} \right)}{-sin\left( \frac{6\theta }{2} \right)sin\left( \frac{2\theta }{2} \right)}

\bf \cfrac{cos(3\theta )cos(\theta )}{-sin(3\theta )sin(\theta )}\implies -\cfrac{cos(3\theta )}{sin(3\theta )}\cdot \cfrac{cos(\theta )}{sin(\theta )}\implies -cot(3\theta )cot(\theta )

8 0
3 years ago
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