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2 years ago

Explain how 2 different squares can be made using the number 9.

Mathematics

1 answer:

faltersainse [42]2 years ago

5 0

You can make two squares with 8, and put a line through one of them making one square two triangles put together.

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Find the perimeter of each polygon 4cm

andriy [413]

Your answer is 12!!!!!

7 0

2 years ago

A pony keg (quarter barrel) of beer contains 62 pints. If the local drinking establishment sells draft beer in 400mL pilsner gl

OLga [1]

1 pint = 473.176 milliliters

62 x 473.176 = 215336.912 milliliters in a pony keg

215336.912/400 = 538.34 glasses

round off answer to 538 glasses

8 0

2 years ago

Please solve (-3×+15)+(-3×+2)

koban [17]

(-3x + 15) + (-3x + 2)
Simplify by combining like terms.
-6x + 17

-6x + 17

3 0

2 years ago

Read 2 more answers

SLOPES PLSSS HELLLLP<br> what goes in the box?

Lisa [10]

Step-by-step explanation:

Water is the universal solvent" with a grain of salt (pun intended). Of course it cannot dissolve everything, but it does dissolve more substances than any other liquid, so the term fits pretty well. Water's solvent properties affect all life on Earth, so water is universally important to all of us.

6 0

2 years ago

Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

2 years ago