Answer:
Yes, the shapes are similar. Note, the angles are equivalent and the sides are scales of each other satisfying the requirements for similarly.
Step-by-step explanation:
For a shape to be similar there are two conditions that must be met. (1) Must have equivalent angles (2) Sides must be related by a scalar.
In the two triangles presented, the first condition is met since each triangle has three angles, 90-53-37.
To test if the sides are scalar, each side must be related to a corresponding side of the other triangle with the same scalar.
9/6 = 3/2
12/8 = 3/2
15/10 = 3/2
Alternatively:
6/9 = 2/3
8/12 = 2/3
10/15 = 2/3
Since the relationship of the sides is the scalar 3/2 (Alternatively 2/3), then we can say the triangles meet the second condition.
Given that both conditions are satisfied, then we can say these triangles are similar.
Note, this is a "special case" right triangle commonly referred to as a 3-4-5 right triangle.
Cheers.
1:4 is you answer. 4-3 is 1 and you do the same to 7
Answer:
roads?
Step-by-step explanation:
i think thats right
13x - y = 3 .....(1)
x - 6y = -33 ......(2)
eqn (2) × 13
13x - 78y = -429 .....(3)
(3) - (1)
13x - 78y = -429
13x - y = 3
(-). (+). (-)
_________________
- 77y = 431
_________________
-77y = 431
y = 431 ÷ -77
y = -5.5
Answer: R would equal -3
Step-by-step explanation:
5 x -3 = -15
-15 + 15 = 0
