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Kamila [148]
3 years ago
10

How do I do vertex in quadratics?How do I graph the quadratic?

Mathematics
1 answer:
nika2105 [10]3 years ago
3 0
What are you trying to figure out
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Alejandra plans to sew fringe on a scarf. The scarf is shaped rectangle. The length of the scarf is 48 inches. The width is one
aleksandr82 [10.1K]
Ok so you will be finding the perimeter of this rectangle. The formula is P(perimeter)=2L(length) + 2W(width)

so the length is 48 and the width is 1/2 of 48, and we all know that 1/2 of 48 = 24 right? so in the formula is says 2L so we will take 48 and multiply it by 2 and get 96. The same way with the width. 24 times 2 = 48 so then we add them together and get 144. Therefore the perimeter and the length of fringe that she will use (or how ever you say it) will be 144 inches.

Hope this helps!;)
5 0
3 years ago
How much will it cost to get 4 tires if the 4th one is free
GarryVolchara [31]
You would have to pay for 3 tires
3 0
3 years ago
Norma's retirement party will cost $24 if she invites 12 guests. If there are 13 guests, how much will Norma's retirement party
blagie [28]

Answer:

If there are 13 guests, it would cost Norma $26

Step-by-step explanation:

Since 12 guest equals 24 dollars all you have to do is divide 24/12 which would give you 2dollars. this means that she has to pay 2 dollars per guest. Multiply 13 becuase you want to know how much money it would cost with 13 guests and you get 26 dollars. Hope this helps.

8 0
3 years ago
Read 2 more answers
Judy simplified the expression (3x + 1)(x – 3) – (2 – 2x2 – 3x). What is the constant term in the simplified expression?
andrey2020 [161]

Answer:

Step-by-step explanation:

(3x+1)(x-3)-(2-2x^2-3x)

3x^2+x-9x-3-2+2x^2+3x

3x^2+2x^2+x-9x+3x-3-2

5x^2-5x-5

the constant term in the simplified expression is -5.

5 0
3 years ago
5.b) If z^(1/2)=x^(1/2)+y^(1/2) , show that (x+y-z)^2=4xy
Rudik [331]

Answer:

Step-by-step explanation:

  • (x+y-z)²= 4xy
  • (x+y-z)²- 4xy = 0
  • (x+y-z)²-(2√x√y)² = 0
  • (x+y-z-2√x√y)(x+y-z+2√x√y) =0
  • [(√x-√y)²-z]*[(√x+√y)²-z]=0
  • (√x-√y)²-z = 0 or (√x+√y)²-z = 0

We have : z^(1/2)= x^(1/2)+y^(1/2) ⇒ √z = √x + √y ⇒ z = (√x + √y)²

  • so (√x+√y)²-z = 0

so (x+y-z)²= 4xy

3 0
3 years ago
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