Answer: $75
Step-by-step explanation: First he bought tires for 45.00 dollars - later sold it as 65.0 dollars.
=> 65 - 45 = 20 dollars is his profit
he brought 3 rims for 85 dollar - then later sold it as 126 dollars
=> 126 - 85 = 41 dollars
He bought headlight for 5.00 dollars then sold it later for 15 dollars.
=> 15 - 5 = 10 dollars
Total expenses
=> 134
Total amount sold
=> 209
Profit => 209 - 134 = 75 dollars
-5/12 would be the answer
Answer:
[-4 1 -2 - 7]
Step-by-step explanation:
[-1 - 2 4 8] + X = [-5 - 1 2 1]
X= [-5 - 1 2 1]- [-1 - 2 4 8]
X=[-5-(-1) - 1-(-2) 2-4 1-8]
X=[-4 1 - 2 - 7]
Answer:
Option C. 3√3
Step-by-step explanation:
Please see attached photo for brief explanation.
In the attached photo, we obtained the following:
Opposite = a
Adjacent = 3
Hypothenus = 6
Angle θ = 60°
We can obtain the value of 'a' as follow:
Tan θ = Opposite /Adjacent
Tan 60° = a/3
Cross multiply
a = 3 x Tan 60°
But: Tan 60° = √3
a = 3 x Tan 60°
a = 3 x √3
a = 3√3
Therefore, the length of the altitude of the equilateral triangle is 3√3.
Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.
To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.
Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.
Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.
Therefore:
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%208%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
The nth root of a can contain negative number only if n is an odd number.
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%202%20%5Ctimes%20-%20%202%20%5Ctimes%20%20%20-%202%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D%20%5C%5C%20%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20-%202%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
Answer