Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
Answer:
a) 1200
b) 150
Step-by-step explanation:
a) total revenue = target amount + expenses
... total revenue = 1000 + 200
... total revenue = 1200
b) total revenue = adult tickets × adult ticket price
... 1200 = adult tickets × 8 . . . . . . . . . . fill in the information you know
... 1200/8 = adult tickets = 150 . . . . . divide by 8
Answer:
Step-by-step explanation:
Answer: -3.5
Step-by-step explanation:
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