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Alinara [238K]
3 years ago
12

What is the solution of the system of equations graphed below?

Mathematics
1 answer:
Dahasolnce [82]3 years ago
6 0

Answer: B

Step-by-step explanation: Look at where the lines intersect

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On his first day of school, Kareem found the high temperature in degrees Fahrenheit to be 76.1°. He plans to use the function to
wolverine [178]
The function for conversions from Fahrenheit to Celsius is:

Celsius = (Fahrenheit - 32) x 5/9 

C(76.1) = (76.1 - 32) x 5/9
             = (44.1) x 5/9
             =  24.5

Therefore, 76.1 degrees Fahrenheit = 24.5 degrees Celsius. 
5 0
3 years ago
Read 2 more answers
I need help with number 19
inysia [295]
Let's start by understanding that the graph is a linear line. We have a common difference if 4.5 for every 10x we have more.

We can start by finding the gradient, using rise over run. Let's take (10, 4.5) and (20, 9)

Our rise is 9 - 4.5 = 4.5 and our run is 10. Then, our gradient becomes 4.5/10 = 0.45

Now, we can substitute points using the point-slope form.

y - 4.5 = 0.45(x - 10)
y - 4.5 = 0.45x - 4.5
Hence, our line becomes y = 0.45x and you can verify by substituting in points from the table.
4 0
3 years ago
The length of each side of an equilateral triangle is 4 1 2 in. find the perimeter of the triangle.
igor_vitrenko [27]
1236inch (5191.2cm)
primeter of a triangle = sum of its threee sides
P.S. 1 inch=4.2 cm
6 0
3 years ago
I need help please ​
ElenaW [278]

Answer:

L = 25

Step-by-step explanation:

Let's call the Length x and width x - 15 since the width is 15 less than length

Eric needs 70 of fencing in total, the perimeter of a rectangle is calculated by adding all sides

x + x + (x - 15) + (x - 15) = 70 add like terms

4x - 30 = 70 add 30 to both sides

4x = 100 divide both sides by 4

x = 25

8 0
3 years ago
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Evaluate the function<br>(x) = 11 – 3x<br>for -2).​
il63 [147K]

Answer:

<h2>17</h2>

Step-by-step explanation:

f(x) = 11 - 3x

f(-2) - <em>put x = -2 to the f(x):</em>

<em />

f(-2) = 11 - 3(-2) = 11 + 6 = 17

3 0
3 years ago
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