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Anni [7]
3 years ago
7

Find the area of the following shape. Show work.

Mathematics
1 answer:
Serga [27]3 years ago
6 0

Answer:

The total area:

12 units²

Step-by-step explanation:

There are three parts on this shape:

1 big right triangle

1 rectangle

1 small right triangle

  • Big right triangle:

area = (4*4)/2 = 16/2 = 8units²

  • Rectangle:

area = 2*1 = 2units²

  • Small right triangle:

area = (2*2)/2 = 2units²

  • Total area

8+2+2 = 12 units²

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--------------------------------------------------------------------------------

Since they each ran 10 meters for a certain amount of time you would multiply the seconds by 5 since 10x5=50

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In the figure, TP and TS are opposite rays. TQ bisects < RTP.
Ket [755]

Answer:

search-icon-image

Class 9

>>Maths

>>Quadrilaterals

>>Quadrilaterals and Their Various Types

>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2

Question

Bookmark

In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28

0

and ∠QRT=65

0

, then find the values of x and y.

463685

expand

Medium

Solution

verified

Verified by Toppr

Given, PQ⊥PS,PQ∥SR,∠SQR=28

∘

,∠QRT=65

∘

According to the question,

x+∠SQR=∠QRT (Alternate angles as QR is transversal.)

⇒x+28

∘

=65

∘

⇒x=37

∘

Also ∠QSR=x

⇒∠QSR=37

∘

Also ∠QRS+∠QRT=180

∘

(Linear pair)

⇒∠QRS+65

∘

=180

∘

⇒∠QRS=115

∘

Now, ∠P+∠Q+∠R+∠S=360

∘

(Sum of the angles in a quadrilateral.)

⇒90

∘

+65

∘

+115

∘

+∠S=360

∘

⇒270

∘

+y+∠QSR=360

∘

⇒270

∘

+y+37

∘

=360

∘

⇒307

∘

+y=360

∘

⇒y=53

∘

Step-by-step explanation:

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