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andrew-mc [135]

3 years ago

8

Rosa is saving money for a trip. She has already saved $250 and plans to save $40 per week. This situation can be represented by

the function f(x)=250+40x, where x is the number of weeks. How much money had rosa saved after 6 weeks?

1 answer:

MissTica3 years ago

6 0

what i got was 490 what i did was first i did 40 times 6 then i added 250 and got 490

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Rlly need help on this ill give brainliest :)

Maksim231197 [3]

Answer:

3^15/5^16

Step-by-step explanation:

(3^3 x 3^6 x 5^-4) / (3^-6 x 5^12)

= (3^3 x 3^6 x 3^6) / (5^12 x 5^4)

= 3^15 / 5^16

4 0

2 years ago

Find the value of x, rounded to the nearest tenth.<br> Correct answers only please..

agasfer [191]

Sin(35) = Opp./Hypo
sin(35) = 18/x
so
x = 18/sin(35)
x = 18 / 0.57357644
x = 31.38
x = 31.4

Answer is C. 31.4

4 0

3 years ago

An airplane flies 2107 miles in 3 hours 35 minutes. What is its average speed in Files per hour?

worty [1.4K]

Answer:

9.8 miles per hour

3·60= 180+35=215 2107÷215=9.8

6 0

2 years ago

Read 2 more answers

Is 267 the largest number in the sum of 3 integers evaluated from 269?

Anni [7]

Yes. it is the largest number

4 0

3 years ago

It is possible to get 2 solutions when the system of equations is: (check all that apply)

SVETLANKA909090 [29]

Answer:

A system of the equation of a circle and a linear equation

A system of the equation of a parabola and a linear equation

Step-by-step explanation:

Let us verify our answer

A system of the equation of a circle and a linear equation

Let an equation of a circle as $x^2+ y^2 = 1$ ..........(1)

Let a liner equation Y = x ............(2)

substitute (2) in (1)

$x^2 + x^2 = 1\\2x^2 = 1\\$

$x^2 = \frac{1}{\sqrt{2} } \\x = +\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$ so Y = $+\frac{1}{\sqrt{2} } , -\frac{1}{\sqrt{2} }$

so the two solution are ( $(\frac{1}{\sqrt{2} } ,\frac{1}{\sqrt{2} }) (-\frac{1}{\sqrt{2} }, -\frac{1}{\sqrt{2} }$ )

A system of the equation of a parabola and a linear equation

Let equation of Parabola be $y^2 = x$

and linear equation y = x

substitute

$x^2 = x\\x^2 - x= 0\\x(x-1) = \\x = 0 , 1$

Y = 0,1

so the two solutions will be (0,0) and (1,1)

3 0

2 years ago