Answer:
ABC= 60 XYZ=540
Step-by-step explanation:
The area of a triangle is 1/2*base*height so for ABC we need to find the height first. To do this we use pythag theorem, and create the equation 13^2=5^2+height^2 rearranging this we can figure out that sqrt(height)=13^2-5^2. For the base we do 2*5 since there are two congruent line segments both equal to 5. Using this we can do 1/2*12*10=area of ABC
For XYZ we can do 1/2*30*36=area of XYZ, we can do 2*15 since there are 2 congruent 15 length line segments at the base.
the correct answer is 2.40
Answer:
98 π R
Step-by-step explanation:
Surface area of sphere = 4 π R²
= 2 π R × 2 R
= 49 π × 2 R
= 98 π R
The answer is 11/36
2/12 chance of rolling fours
because there are 2 sides containing a four on both dice combined and 12 sides in total.
Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.
I personally like to imagine a box like this:
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.
1/6 * 1/6 = 1/36 chance to roll double of ones
And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:
1/36 * 5 = 5/36
So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:
5/36 + 2/12 =
5/36 + 6/36 =
11/36
