First you find the common deoninator.
Step 1: Reduce (simplify) entered fractions to lowest terms, if the case:Fraction: 5 / 6 it's already reduced to lowest terms
Fraction: 11 / 12 it's already reduced to lowest terms
Step 2: Calculate LCM (lowest common multiple) of the reduced fractions' denominators, it will be the common denominator of the compared fractions:Denominator 6, factored = 2 * 3
Denominator 12, factored = 22<span> * 3</span>
LCM (6, 12) = 22<span> * 3 = 12</span>Step 3: Calculate each fraction's expanding number (LCM divided by each fraction's denominator):For fraction: 5 / 6 is 12 : 6 = (22<span> * 3) : 6 = 2</span>
For fraction: 11 / 12 is 12 : 12 = (22<span> * 3) : 12 = 1</span>
Step 4: Expand fractions to bring them to the common denominator (LCM):5 / 6 = (2 * 5) / (2 * 6) = 10 / 12
<span>11 / 12 = (1 * 11) / (1 * 12) = 11 / 12</span>
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa
<span>Your bowl contains 8 red balls, and 9 blue balls, and you draw 4 balls. in how many ways can the selection be made so that at least one of each color is drawn.</span>
If a diagram has a scale of 1:100, that means that the real thing is 100 times larger. To find how long the real thing is, that means that we need to multiply the length on the diagram by 100. 100 * 15 is 1500. But, that is 1,500 cm. To convert it into meters, we need to divide by 100. That's because there's 100 centimeters in every meter. 1500/100 is 15, which means that the actual length of the car park is 15 meters.