I don't understand the problem
1 answer:
You might be interested in
Answer:
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
And the 90% confidence interval would be given (0.131;0.169).
Step-by-step explanation:
We have the following info given:
represent the sampel size slected
number of students who read above the eighth grade level
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
The confidence interval for the proportion would be given by this formula
For the 90% confidence interval the significance is and
, with that value we can find the quantile required for the interval in the normal standard distribution and we got.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.131;0.169).
For this case we have to:
x: Let the variable representing the unknown number
We algebraically rewrite the given expression:
Twice a number plus 10, is represented as:
Three times that number less 4. is represented as:
Thus, the complete expression is:
Subtracting 3x from both sides of the inequality:
Subtracting 10 from both sides of the inequality:
Equal signs are added and the same sign is placed:
We multiply by -1 on both sides, taking into account that the sense of inequality changes:
The solution is given by all values of "x" less than 14.
Answer: