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11111nata11111 [884]
4 years ago
10

I don't understand the problem

Mathematics
1 answer:
Rasek [7]4 years ago
5 0
The answer is D.
18 2/3÷2/3
18.66÷2/3
27.99
28
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PLS HELP !!!! WILL MARK BRAINLIEST !!
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Answer: Choice C) no solution

=============================================================

Explanation:

The first equation says that y and 3x-4 are the same thing.

So we can replace every copy of "y" in the second equation with "3x-4" like so

9x - 3y = 14

9x - 3(3x-4) = 14

9x - 9x + 12 = 14

0x + 12 = 14

0 + 12 = 14

12 = 14

The last equation is false because we get different values on either side. Because the last equation is false, it means the equation 9x-3y = 14 is false when y = 3x-4.

In short, the overall systems of equations is inconsistent and that leads to no solution (choice C).

If you were to graph each equation, you should find that both lines are parallel. Parallel lines never intersect. The solution is the intersection point of any graphed system.

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Answer:

decimal form: 0.0357

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Step-by-step explanation:

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The mean height of women in a country​ (ages 20minus​29) is 64.2 inches. A random sample of 75 women in this age group is select
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Answer:

z=\frac{65-64.2}{\frac{2.84}{\sqrt{75}}} = 2.440

And we can find the probability using the complement rule and with the normal standard table like this:

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The probability that the mean height for the sample is greater than 65 inches is 0.007

Step-by-step explanation:

Let X the random variable that represent the women heights of a population, and we know the following parameters

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Since the sample size selected is 75>30 we can use the centrel limit theorem and the appropiate formula to use would be the z score given by:

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If we find the z score for 65 inches we got:

z=\frac{65-64.2}{\frac{2.84}{\sqrt{75}}} = 2.440

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P(Z>2.440) =1-P(Z

The probability that the mean height for the sample is greater than 65 inches is 0.007

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Step-by-step explanation:

A mathematical way of expressing profit is to use a positive number. A negative number is used to express a loss

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Assume that the playbook contains 10 passing plays and 12 running plays. The coach randomly selects 9 plays from the playbook. W
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