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2 years ago

1.9^4 × 10 × 2.9 x 10^1

Mathematics

2 answers:

kvasek [131]2 years ago

8 0

Are you sure the question isn’t 1.9 x 10^4 x 2.9 x 10^1 = (1.9 x 2.9) x (10^4 x 10^1) = 5.51 x 10^5

nlexa [21]2 years ago

4 0

3779.309 is the answer....

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help me plz:Morgan fills a 1-liter jar with water from the pond.She uses a 100-ML cup to scoop water out of the pond and pour it

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3 years ago

–2 times the quantity q minus 3

Mandarinka [93]

Answer:

This question was worded weirdly however I am assuming this is algebra and you need the equation. So here- -2(q-3) or -2q+6

Step-by-step explanation:

Distribute the -2, to all the terms in the parenthesis of -2(q-3) you get 2q+6

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3 years ago

Alexis is 5 feet tall. Determine Alexis’ height in centimeters, if one inch is equal to 2.54 centimeters.

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Alexis is 152.4 centimeters tall

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3 years ago

Customers experiencing technical difficulty with their Internet cable hookup may call an 800 number for technical support. Itake

Paladinen [302]

Answer:

(A) The percent of the problems takes more than 5 minutes to resolve is 60.87%.

(B) The problem solving time will be 50% as long as the difference between the two end points is 5.75.

(D) Mean = 6.25 minutes, Standard deviation = 3.32 minutes

Step-by-step explanation:

Let the random variable X represent the time it takes the technician to resolve the problem.

The random variable X follows an Uniform distribution with parameters a = 0.50 minutes and b = 12 minutes.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(A)

Compute the probability that the problems takes more than 5 minutes to resolve as follows:

$P(X>5)=\int\limits^{12}_{5}{\frac{1}{12-0.50}}\, dx$

$=\frac{1}{11.50}\cdot \int\limits^{12}_{5}{1}\, dx \\\\=\frac{1}{11.50}\cdot [x]\limits^{12}_{5}\\\\=\frac{1}{11.50}\cdot [12-5]\\\\=\frac{7}{11.50}\\\\=0.608696\\\\\approx 0.6087$

Thus, the percent of the problems takes more than 5 minutes to resolve is 60.87%.

(B)

Let the middle 50% of the problem-solving times be between u and v.

Then,

P (u < X < v) = 0.50

$\int\limits^{v}_{u}{\frac{1}{12-0.50}}\, dx=0.50\\\\\frac{1}{11.50}\cdot \int\limits^{v}_{u}{1}\, dx=0.50\\\\\frac{v-u}{11.50}=0.50\\\\(v-u)=5.75$

Thus, the problem solving time will be 50% as long as the difference between the two end points is 5.75.

(C)

The interval in which the technician can solve the problem is 30 seconds to 12 minutes.

So, the values of a and b in minutes is:

a = 30 seconds = 0.50 minutes

b = 12 minutes.

(D)

The mean time is:

$\mu=\frac{a+b}{2}=\frac{0.50+12}{2}=6.25\ \text{minutes}$

The standard deviation of the time is:

$\sigma=\sqrt{\frac{(b-a)^{2}}{12}}=\sqrt{\frac{(12-0.50)^{2}}{12}}=3.3197\approx 3.32\ \text{minutes}$

5 0

3 years ago

Let f(x) = 2x +5 and g(x) = x2 - 8x + 15. Perform f(x) · g(x) HELP

LekaFEV [45]

-16x^2-10x+75
Answer^

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3 years ago