Answer:
Step-by-step explanation:
tanx=27/38
take the inverse...
tan^-1(27/38)
≈35.4 degrees
Hey there!!
Remember : R = range and f ( x ) = y and y = range
R : { 5 , 6 , 7 , 8 }
( 1 ) 5 = 1 x / 2 + 4
... 5 - 4 = x / 2
... 1 = x / 2
... x = 2 = ( 2 , 5 )
( 2 ) 6 = x / 2 + 4
... 2 = x / 2
... x = 4 = ( 4 , 6 )
( 3 ) 7 = x / 2 + 4
... 3 = x / 2
... x = 6 = ( 6 , 7 )
( 4 ) 8 = x /2 + 4
... 4 = x/2
... x = 8 = ( 8 , 8 )
Hope my answer helps!
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
<span>
</span>
Answer:
y= 5x+2
Explanation:
slope is 5 and the y-intercept is 2.
