What is the equation of the circle with a diameter of 6 units and a center located at (2, −5) on the coordinate plane? a A b B c

Question

3 years ago

10

C d D

1 answer:

Nastasia [14] · Answer 1 · 2022-06-21T22:24:41+03:00

6 0

Answer:

$(x-2)^2+(y+5)^2=36$

Step-by-step explanation:

Recall that the equation of a circle of radius R centered at $(x_0,y_0)$ is given by:

$(x-x_0)^2+(y-y_0)^2=R^2$

For your particular case: R = 6, $x_0$ = 2, and $y_0$ = -5, therefore the equation becomes:

$(x-x_0)^2+(y-y_0)^2=R^2\\(x-2)^2+(y-(-5))^2=6^2\\(x-2)^2+(y+5)^2=36$