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mash [69]
3 years ago
10

What is the equation of the circle with a diameter of 6 units and a center located at (2, −5) on the coordinate plane? a A b B c

C d D
Mathematics
1 answer:
Nastasia [14]3 years ago
6 0

Answer:

(x-2)^2+(y+5)^2=36

Step-by-step explanation:

Recall that the equation of a circle of radius R centered at (x_0,y_0) is given by:

(x-x_0)^2+(y-y_0)^2=R^2

For your particular case: R = 6, x_0 = 2, and y_0 = -5, therefore the equation becomes:

(x-x_0)^2+(y-y_0)^2=R^2\\(x-2)^2+(y-(-5))^2=6^2\\(x-2)^2+(y+5)^2=36

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