Enlargement because all sides are being multiplied by 3 times their original amount making if it were a scale factor that were a fraction then it would be a reduction
To solve this problem, let us first assign variables. Let
us say that:
A = runner
B = cyclist
d = distance
v = velocity
time = t
The time in which the cyclist overtakes the runner is the
time wherein the distance of the two is the same, that is:
dA = dB
We know that the formula for calculating distance is:
d = v t
therefore,
vA tA = vB tB
Further, we know that tA = tB + 2, therefore:
vA (tB + 2) = vB tB
4 (tB + 2) = 14 tB
4 tB + 8 = 14 tB
10 tB = 8
tB = 0.8 hours = 48 min
Therefore the cyclist overtakes the runner after 0.8
hours or 48 minutes.
D because i did this alreadyyy
In all these expressions you have a power of a power.
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
.
11) (n^4)^8 = n^(4×8) = n^32
13) (q^10)^10 = q^(10×10) = q^100
15) (x^3)^-5 = x^[3×(-5)] = x^(-15)
17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5
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19) (c^3)^5(d^3)^0 = c^(3</span>×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15
