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nataly862011 [7]
2 years ago
13

Write the point-slope equation of the line that passes through (3, -1) and a slope of 2.

Mathematics
2 answers:
fredd [130]2 years ago
5 0

Answer:

\large\boxed{y+1=2(x-3)}

Step-by-step explanation:

The point-slope form of the equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

We have the slope m = 2 and the point (3, -1). Substitute:

y-(-1)=2(x-3)\\\\y+1=2(x-3)

goblinko [34]2 years ago
4 0

Answer:

y=2x+(-7)

Step-by-step explanation:

y=2x+c

solve for c

-1=2(3)+c

-1=6+c

-6-1=c

c=-7

<u>y=2x+(-7)</u>

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The graph box linear function f passes through the point (1, -9) and has a slope of 3
Marat540 [252]

9514 1404 393

Answer:

  C) 4

Step-by-step explanation:

The point-slope equation of the line is ...

  y -k = m(x -h) . . . . . line with slope m through point (h, k)

  y +9 = 3(x -1) . . . . . line with slope 3 through point (1, -9)

For y=0 (the 0 of the function), we have ...

  9 = 3(x -1)

  3 = x -1

  4 = x

The x-intercept is (4, 0).

3 0
2 years ago
Which line has a slope of 5/2?
Lorico [155]
The answer is line c, because you have to rise 5 and run 2.
8 0
3 years ago
Read 2 more answers
Write the ordered pair that represents YZ. Then find the magnitude of YZ. y(-4,12), Z(1,19).
ki77a [65]

The magnitude of YZ is 8.6

<u>Explanation:</u>

<u />

Y( -4, 12)

Z ( 1, 19)

Magnitude of YZ = ?

We know:

YZ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

On substituting the value we get:

YZ = \sqrt{(1+4)^2 + (19 - 12)^2} \\\\YZ = \sqrt{(5)^2 + (7)^2} \\\\YZ = \sqrt{25+49} \\\\YZ = \sqrt{74} \\\\YZ = 8.6

Thus, the magnitude of YZ is 8.6

6 0
3 years ago
Read 2 more answers
I need to know the values of m and n.
Darina [25.2K]

Answer:

A) 32 and 28

Step-by-step explanation:

A= √4².√2

= √16.√2

= √32

m= 32

B= √2². √7

=√4.√7

=√28

n= 28

3 0
2 years ago
An art studio purchased a triangular plot of land in a town and constructed a new building whose base is in the shape of a right
Vinvika [58]

Answer:

The sides are 30 ft, 40 ft and 50 ft.

Step-by-step explanation:

The length of the triangle are as follows x - 4 , x + 6 and 2x - 18 . The hypotenuse should be 2x - 18 . The hypotenuse is the longest side of a right angle triangle.

Using Pythagoras theorem the length of the sides can be found.

a² + b² = c²

(x - 4)² + (x + 6)² = (2x - 18)²

(x - 4)(x - 4) + (x + 6)(x + 6) = (2x - 18)(2x - 18)

x²- 4x - 4x + 16 + x² + 6x + 6x + 36 = 4x² - 36x - 36x + 324

2x² - 8x + 12x + 16 + 36 = 4x² - 72x +  324

2x² + 4x + 52 = 4x² - 72x +  324

2x² - 4x² + 4x + 72x + 52 - 324 = 0

-2x² + 76x - 272 = 0

2x² - 76x + 272 = 0

divide through by 2

x² - 38x + 136 = 0

find the number you can multiply to give you 136 and add to give you - 38. The number are - 34 and - 4.

x² - 4x - 34x + 136 = 0

x(x - 4) - 34(x - 4) = 0

(x - 4)(x - 34 ) = 0

x = 4 or 34

we can only use 34 since using 4 will result to negative number.

x - 4  = 34 - 4 = 30 ft

x + 6 = 34 + 6 = 40 ft

2x - 18 = 68 - 18 = 50 ft

6 0
2 years ago
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