Question

Write the point-slope equation of the line that passes through (3, -1) and a slope of 2.

Answer 1

Answer:

$\large\boxed{y+1=2(x-3)}$

Step-by-step explanation:

The point-slope form of the equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point

We have the slope m = 2 and the point (3, -1). Substitute:

$y-(-1)=2(x-3)\\\\y+1=2(x-3)$

Answer 2

Answer:

y=2x+(-7)

Step-by-step explanation:

y=2x+c

solve for c

-1=2(3)+c

-1=6+c

-6-1=c

c=-7

y=2x+(-7)