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Sindrei [870]
3 years ago
6

Make y the subject of the relation; m over y = tan 46⁰​

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0
I don’t know the answer to this sorry
You might be interested in
The expression 7z-9p+9z-z
nika2105 [10]

Answer:

15z - 9p

Step-by-step explanation:

7z - 9p + 9z - z

=7z - 9p +8z

= -9p + 15z or 15z - 9p Answer

Hope this helps!

4 0
3 years ago
Order these numbers from least to greatest. −3.12 , −3.2 , 8 , −5216
trapecia [35]
From the least to the greatest.

The one with the biggest size and has a negative sign is the least

-5216, -3.2, -3.12, 8
8 0
3 years ago
You decide to put $5000 in a savings account to save $6000 down payment on a new car. If the account has an interest rate of 7%
bezimeni [28]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$6000\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years \end{cases}

\bf 6000=5000\left(1+\frac{0.07}{12}\right)^{12\cdot t}\implies \cfrac{6000}{5000}\approx (1.0058)^{12t}\implies \cfrac{6}{5}\approx(1.0058)^{12t} \\\\\\ \log\left( \cfrac{6}{5} \right)\approx \log[(1.0058)^{12t}]\implies \log\left( \cfrac{6}{5} \right)\approx 12t\log(1.0058) \\\\\\ \cfrac{\log\left( \frac{6}{5} \right)}{12\log(1.0058)}\approx t\implies 2.63\approx t\impliedby \textit{about 2 years, 7 months and 16 days}

6 0
3 years ago
Can you please help me out on this one ​
vampirchik [111]

Answer:

9

Step-by-step explanation:

You need to divide 54 by 6

4 0
3 years ago
Read 2 more answers
PLS HELP ME I WILL GIVE YOU BRAINLIEST!
dezoksy [38]
I think its 180 i think
5 0
3 years ago
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