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____ [38]
3 years ago
11

Et f(x) = 9x − 2 and g(x) = −x + 3. find f(g(x)). −9x − 2 −9x + 5 −9x + 25 −9x + 27

Mathematics
2 answers:
svetlana [45]3 years ago
5 0

Answer:

its a on edg

Step-by-step explanation:

im 100%

Zielflug [23.3K]3 years ago
4 0
Hello : 
<span>f(x) = 9x − 2 and g(x) = −x + 3.
</span><span> f(g(x)) = f (-x+3) = 9(-x+3)-2
</span> f(g(x)) = = -9x +25

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Answer:

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Hello i need urgent help with this assignment.
Mars2501 [29]

Answer:

AD = 1 3/4y + 5/8x - 3

Step-by-step explanation:

AD = 1/4x + 2y + 3 - 1/4y + 3/8x - 6

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AD = 1 3/4y + 5/8x - 3

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3 years ago
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Answer:

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6 0
4 years ago
Determine the utilization and the efficiency for each situations:A. A loan processing operation that processes an average of 7 l
Vera_Pavlovna [14]

Answer:

A) Utilization = 70%

Efficiency = 87.5%

B) Utilization = 66.67%

Efficiency = 80%

Step-by-step explanation:

Determine the utilization and the efficiency for each situations:

A. A loan processing operation that processes an average of 7 loans per day. The operation has a design capacity of 10 loans per day and an effective capacity of 8 loans per day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = 7 loans per day

Design capacity = 10 loans per day

Utilization = 7/10 × 100

= 70%

Efficiency = Actual output / Effective capacity × 100

Actual output = 7 loans per day

Effective capacity = 8 loans per day

Efficiency = 7/8 × 100

= 87.5%

B. A furnace repair team that services and average of four furnaces a day if the design capacity is six furnaces a day and the effective capacity is five furnaces a day.

Formula for Utilization = Actual Output /

Design Capacity × 100

Actual output = four furnaces a day

Design capacity = six furnaces a day

Utilization = 4/6 × 100

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Efficiency = Actual output / Effective capacity × 100

Actual output = four furnaces a day

Effective capacity = five furnaces a day

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6 0
3 years ago
Which quadratic equation has the roots -1+4i and -1-4i
AysviL [449]

Answer:

C

Step-by-step explanation:

Solve the quadratic in answer choice C using the quadratic formula:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

Here a=1, b=2, and c=17.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-2+/-\sqrt{(-2)^2-4(1)(17)} }{2(1)}=\frac{-2+/-\sqrt{4-68}}{2)}

\frac{-2+/-\sqrt{-64} }{2}=\frac{-2+/-8i }{2}=-1+/- 4i


6 0
4 years ago
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