The ratio of red to green is 5:6 which means that for every 5 red cars, there are 6 green cars
The ratio of green to blue is 3:10 telling us that for every 3 green cars, there are 10 blue cars.
The ratio 3:10 is equivalent to 6:20 after we multiply both parts by 2. This now says that for every 6 green cars, there are 20 blue cars.
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Let's say we had 5 red cars, 6 green cars and 20 blue cars
Based on that info, we know that the ratio of red to green is 5:6
And the ratio of green to blue is 6:20 which reduces to 3:10
We don't reduce 6:20 to 3:10 however, since that would change the green count from 6 to 3. We want to keep the green count at 6.
So because there are 5 red cars, 6 green cars, and 20 blue cars in this example, and this example points to the proper ratios mentioned earlier, this means that the final answer is 5:6:20. This ratio cannot be reduced or simplified as there are no common factors (other than 1) for 5, 6, and 20.
D , because they are both completely unrelated which means one does not depend on the other. bringing an umbrella is independent from going to school knowing u have a test.
Answer:
12) A = 27
13) B = 36
14) C = 25
15) D = 30
Step-by-step explanation:
We need to complete the ratio tables
We are given:
Footballs 15 5 20 C D
Baseballs A 9 B 45 54
The table shows the ratio of footballs to baseballs.
We are given the ratio 
All other ratios will also be simplified to get 
12) Calculate A
Footballs = 15
Baseballs = A
Common ratio is 5/9, we need to find a number that multiplies by 5 to get 15, same number will be multiplied by denominator to get A.
We know that 
So, A = 27
13) Calculate B
Footballs = 20
Baseballs = B
Common ratio is 5/9, we need to find a number that multiplies by 5 to get 20, same number will be multiplied by denominator to get B.
We know that 
So, B = 36
14) Calculate C
Footballs = C
Baseballs = 45
Common ratio is 5/9, we need to find a number that multiplies by 9 to get 45, same number will be multiplied by numerator to get C.
We know that 
So, C = 25
15) Calculate D
Footballs = D
Baseballs = 54
Common ratio is 5/9, we need to find a number that multiplied by 9 to get 54, same number will be multiplied by numerator to get D.
We know that 
So, D = 30
Answer:
gradient = -10
y intercept = 1
Step-by-step explanation:
y = mx + b
y = -10x + 1
m = slope ; hence, slope = -10 in the eqn
y intercept = when x = 0
y = -10(0) + 1
y = 1
Let y = ax²+bx+c then substitute all of orders. we'll be doing equations system.

Ok we are at this.
Substitute c = 3 into equation 1 and equation 3.


then addition and subtract for a-b = 3 and a+b = -1

Therefore a = -2, substitute a = -2 in a-b+c=0 or a+b+c=2 but i'm doing a-b+c=0 one.

Therefore b = 1, substitute both a, b and c into y=ax²+bx+c as we get,
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