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miss Akunina [59]
3 years ago
12

Matt has five times as many stickers as David David has d stickers and Matt has m stickers, and Matt gives David 8 slideshow man

y stars des each have in m In terms of d, how many stickers does Matthave, after giving David stickers? (Type an expression using d as the variable) Enter your answer in the answer box and then click Check Answer
Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

Matt has 5d - 8 stickers now.

Step-by-step explanation:

For this problem, David has d stickers and Matt has m stickers. We know Matt has 5 times as many stickers as David so m = 5d.

David = d

Matt = 5d

If Matt gives David 8 slides, now Matt has 5d - 8 stickers.

So, after giving David 8 stickers, Matt has 5d-8 stickers.

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The 2th term of The A.P is 7 and 4th term is 28 Find The Common difference and The first term.
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Answer:

d = 10.5, a₁ = - 3.5

Step-by-step explanation:

The n th term of an AP is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₂ = 7 and a₄ = 28 , then

a₁ + d = 7 → (1)

a₁ + 3d = 28 → (2)

Subtract (1) from (2) term by term to eliminate a₁

2d = 21 ( divide both sides by 2 )

d = 10.5 ← common difference

Substitute d = 10.5 into (1)

a₁ + 10.5 = 7 ( subtract 10.5 from both sides )

a₁ = - 3.5 ← first term

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Step-by-step explanation:

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