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Leokris [45]
3 years ago
8

I love you pls help me im hopeless

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

46°

Step-by-step explanation:

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How do you simplify the equation useing like terms: 8r+12p-7-3p
stiks02 [169]

Answer:

8r+9p-7

Step-by-step explanation:

12p-3p=9p

8r+9p-7

7 0
3 years ago
See attachment for problem
Effectus [21]

The liters in the tank when it is filled to a height of 3.70 is  5,580 liters

The liters that needs to be added to 100% capacity is 480 liters

<h3>What is the volume?</h3>

A right circular cone is a three dimensional object has a flat circular base that tapers to a vertex. The volume of a right circular cone is the amount of space in the right circular cone.

Volume of a cone = 1/3(πr²h)

Where:

  • π = pi = 3.14
  • r = radius
  • h = height

Volume of the right circular cone when its filled to a height of 3.70 = 1/3 x 3.14 x 3.70 x 1.20² = 5.58 m³

5.58 x 1000 = 5,580 liters

Volume of the right circular cone when it is full =  1/3 x 3.14 x 4 x 1.20² = 6.03  m³

6.03 x 1000 = 6030 liters

Liters that needs to be added to 100% capacity =  6030 liters - 5,580 liters  = 480 liters

To learn more about the volume of a cone, please check: brainly.com/question/13705125

#SPJ1

7 0
1 year ago
Identify the property used in the first five steps to solve the equation 2(x – 5) - 6x= -22
USPshnik [31]
<span>To answer this question, you need to multiply the number inside the bracket first. Then you can move the number to the right side of the equal sign and keep the x on the left side of the equal sign. The step would be like this

2(x – 5) - 6x= -22
(2x - 10) - 6x = -22
2x - 6x  = -22 +10
-4x= -12
x= -12/-4
x=3</span>
4 0
3 years ago
8 - 6 ÷ 3 + 11 =<br><br> what is the answer
Murrr4er [49]

Answer:

17

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Bonita said that the product of 5/6 times 1 2/3= 7/3. How can you tell that her answer is wrong?
Masja [62]

Answer:

B. 5/6 of a number cannot be greater than the number.

7/3 = 2 1/3 > 1 2/3

6 0
2 years ago
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