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3 years ago

On a menu, each item from column A costs $2.25, each item from column B costs $4.50, and each item from column C costs $5.25.

Mathematics

2 answers:

Jet001 [13]3 years ago

7 0

Insert the numbers. add them, and look for which statement is true.

<u>Terry</u>

4(2.25) + 5.25 = 14.25

2(2.25) + 2(4.5) = 13.5

<u>Maria</u>

2.25 + 4.5 + 5.25 = 12

<h3>The statement that is true is C, Terry's meal ($14.25) cost more than John's ($13.50) and Maria's ($12.00).</h3>

Bezzdna [24]3 years ago

5 0

Answer = C.
Explanation above says how I worked it out too

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3 years ago

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the table shows the types of popcorn buckets sold at a concession station for one day. what percent of the buttered popcorn buck

vlada-n [284]

Hi there! The answer is about 23%

First we need to find the total amount of buttered popcorn sold. This is 182 + 140 + 97 = 419 buckets.

To find the percentage of the buttered popcorn buckets that were large, we use the following formula:
$\frac{part}{total} \times 100\%$

Filling in this formula brings us to our answer:
$\frac{97}{419} \times 100\% = 23.15$
Hence, the answer is about 23%

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3 years ago

Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5

zaharov [31]

Answer:

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

$\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}$ or $\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}$

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

$\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}$

Therefore, the solution is 31.

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Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as $\displaystyle \large{a_{n-1} \cdot r = a_n}$ meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as: