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Leya [2.2K]
3 years ago
7

a square is a figure with two pairs of parallel sides and four write angles. is the statement a good definition? if not find a c

ounterexample
Mathematics
2 answers:
Ahat [919]3 years ago
7 0
The statement is not a good definition.

A counterexample is a rectangle.

A rectangle has two pairs of parallel side and four right angles, but it is not a square.
sertanlavr [38]3 years ago
5 0
No, because that could easily be defining a rectangle as well as a square.

A square is a figure with two pairs of parallel sides of the same length, and four right angles.
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Midpoint of (2,4) and (2, -7)
slega [8]

Step-by-step explanation:

soln:

let,

(x1,y1) =(2,4)

(x2,y2)=2,-7)

Now,

By midpoint formula,

×= <u>x</u><u>1</u><u>+</u><u>x</u><u>2</u>

2

= <u>2</u><u>+</u><u>2</u>

2

=<u>4</u>

2

=2,,

And,

Y=<u>y</u><u>1</u><u>+</u><u>y</u><u>2</u>

2

=<u>4</u><u>-</u><u>7</u>

2

= <u>-</u><u>3</u>

2

Hence ,

The mispoint between points (2,4) and (2,-7) is (2,<u>-</u><u>3</u><u> </u><u> </u><u> </u><u>)</u>

2

6 0
2 years ago
The vertex of a parabola is ( 3, -1). One point on the parabola is
Rudik [331]

Answer:

Step-by-step explanation:

If you plot the vertex and the point, you see that the point is above the vertex. Therefore, this is a positive parabola with the work form of

y=a(x-h)^2+k

We have values for x, y, h, and k. Let's write the equation of the parabola, put it into function notation, then find another x value at which to evaluate it.

8=a(6-3)^2-1 and

8=a(3)^2-1 and

8 = 9a - 1 and

9 = 9a so

a = 1. The equation of the parabola in function notation is

f(x)=(x-3)^2-1

Since the vertex is at (3, -1) it would make sense to evaluate the function at x values close to the vertex. Let's evaluate the function at an x value of 4:

f(4)=(4-3)^2-1 and

f(4)=(1)^1-1 and

f(4) = 0. That means that another point on this parabola will be (4, 0).

8 0
4 years ago
Please everyone, I need help with this question and it's worth 10 good points.
umka21 [38]
9 is the right answer
3 0
3 years ago
Y=(x-3)^2-4
Ne4ueva [31]
<h2>Steps:</h2>
  • Vertex Form: y = a(x - h)² + k with (h,k) as the vertex

So firstly, let's start with the vertex. Since this is in vertex form, we can find the vertex easily. Since 3 is in the h variable and -4 is in the k variable, <u>the vertex is (3,-4).</u>

Next, the axis of symmetry. Remember that the vertex's x-coordinate and the axis of symmetry are the same. In this case, since the vertex's x-coordinate is 3, this means that <u>the axis of symmetry is x = 3.</u>

Next, whether the vertex is a minimum or a maximum. To determine whether it's a minimum or a maximum, we look towards the a variable of the vertex form. If a is negative, then the parabola opens down and the vertex is a maximum. However, if a is positive, then the parabola opens up and the vertex is a minimum. In this case, a = 1 and since 1 is positive, <u>this makes the vertex a minimum.</u>

Next, to find the y-intercept plug 0 into the x-variable and solve:

y=(0-3)^2-4\\y=(-3)^2-4\\y=9-4\\y=5

<u>The y-intercept is (0,5).</u>

Next, to find the x-intercepts plug 0 into the y-variable to solve. Since it's a bit less straightforward than finding the y-intercept, I will walk through the steps:

0=(x-3)^2-4

Firstly, add 4 to both sides:

4=(x-3)^2

Next, square root both sides:

\pm\ 2=x-3

Next, add 3 to both sides:

3\pm2=x

Lastly, solve the left side twice: once with the plus sign, once with the minus sign:

3+2=x\\5=x\\\\3-2=x\\1=x

<u>Your x-intercepts are (5,0) and (1,0).</u>

<h2>Answers:</h2>

In short:

  • Vertex: (3,-4)
  • x-intercept(s): (5,0) and (1,0)
  • y-intercept(s): (0,5)
  • Axis of symmetry: x = 3
  • Minimum or Maximum? Minimum.
5 0
3 years ago
Which verbal expression best describes the algebraic expression 2x ÷ 4?
lakkis [162]
The one that makes most sense is the last one, but I would define it as "Two times some number divided by 4".
5 0
3 years ago
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