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ElenaW [278]
2 years ago
12

in how many ways can 4 mangoes and 3 apples be distributed among 7 children if each child receives only 2 fruit?​

Mathematics
1 answer:
abruzzese [7]2 years ago
7 0

solution

this is what I did. total number of ways without any restriction =900. we have to subtract the case when at least one child doesn't get any fruit. let that be C1∪C2∪C3 and we use the principle of mutual inclusion and exclusion to find that. C1∪C2∪C3=C1+C2+C3−(all two intersections)+3 intersections (no one gets a fruit case) =3⋅60−3+1=178 so case where each child gets at least one fruit =900−178=722.

Is this right, someone saying answer =49

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