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3 years ago

Graph the line. y+2=-1/(x-1)

Mathematics

1 answer:

Airida [17]3 years ago

4 0

Answer:

I can't graph on here but to graph you start at the starting point which is -1 in the y-axis. So we start at -1 on the y-axis then we carry out the slope which is -1. Because the slope is negative the graph will be negative so you move down 1 and right 1 continuously.

Step-by-step explanation:

To graph the line you have to put it in y = mx + b form

So first let's distribute

y + 2 = -1x + 1

Subtract 2 from both sides

y = -1x - 1 OR y = -x - 1

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On two investments totaling $11,500, Peter lost 3% on one and earned 4% on the other. If his net annual receipts were $⁢201, how

BlackZzzverrR [31]

Total amount of money invested - $11500
X +Y = $11500. ----------(1)
Total yearly interest for thetwo a/c is - $201
-0.03X + 0.04Y = $201
Form (1)
X = 11500 - Y
Substitute for X
-0.03(11500 - Y) + 0.04 Y = $201
-345 + 0.03Y + 0.04Y =201
0.07Y = 546
Y = 7800 at 4 %
Calculate X
X = 11500 - Y
= 11500 - 7800
=3700 at - 3%
Check
-0.03×3700 + 0.04 × 7800 = $201
-111 + 312 = $201
$201 = $201

6 0

3 years ago

A boy bought 9 new cards to add to his card collection of 25 cards. The next day his dog ate half of his collection. How many ca

lora16 [44]

This would equal (9+25)/2

Which could be simplified into 34/2

Which means the answer is 17

4 0

3 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.