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3 years ago

Asap po please thank you po!

Mathematics

1 answer:

eduard3 years ago

8 0

Answer:

1 is correct, 100.

2 is 500, not 470. since we're rounding to the nearest hundred, we would look at the tens place and if it's higher than 5 then round up.

3 is correct.

4 is correct.

5 is correct.

6 is correct.

7 is correct.

8 is 290, not 300. like i said before, but in this case we're rounding t the nearest ten instead of hundred. but the same rules apply.

9 is correct.

and 10 is correct!

i think that you did pretty well on most of these, but remember the rounding rule.

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How do you do this problem?

Vadim26 [7]

Answer:

Your answer is absolutely correct

Step-by-step explanation:

The work would be as follows:

$\int _0^{\sqrt{\pi }}4x^3\cos \left(x^2\right)dx,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> 4\cdot \int _0^{\sqrt{\pi }}x^3\cos \left(x^2\right)dx\\\\\mathrm{Apply\:u-substitution:}\:u=x^2\\=> 4\cdot \int _0^{\pi }\frac{u\cos \left(u\right)}{2}du\\\\\mathrm{Apply\:Integration\:By\:Parts:}\:u=u,\:v'=\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\int \sin \left(u\right)du\right]^{\pi }_0\\\\$

$\int \sin \left(u\right)du=-\cos \left(u\right)\\=> 4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0\\\\\mathrm{Simplify\:}4\cdot \frac{1}{2}\left[u\sin \left(u\right)-\left(-\cos \left(u\right)\right)\right]^{\pi }_0:\quad 2\left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0\\\\\mathrm{Compute\:the\:boundaries}:\quad \left[u\sin \left(u\right)+\cos \left(u\right)\right]^{\pi }_0=-2\\=> 2(-2) = - 4$

Hence proved that your solution is accurate.

3 0

4 years ago

Read 2 more answers

1/8(-8c+16)-1/3(6+3c)

Misha Larkins [42]

$\frac{1}{8}(-8c+16) - \frac{1}{3}(6+3c)$

This may look scary, but all you have to do is distribute, first:
$(-c+2)-(2+c)$

Now it's much easier (remember to distribute the negative):
$-c+2-2-c = -2c$

So, the entire thing simplifies to -2c. NEAT!

4 0

3 years ago

Read 2 more answers

a stack of boards is 24 inches high. Each board is 3/8 of an inch thick. How many boards are in the stack?

meriva

To answer this we need to divide 24 by 3/8.

First we need to convert 24 to a fraction.

$\frac{24}{1}$

When dividing fraction, multiply the first fraction by the reciprocal of the second fraction. (A reciprocal is an upside down fraction)

$\frac{24}{1} * \frac{8}{3} = \frac{192}{3}$ (simplify:) 64

The answer is 64

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)

4 0

3 years ago

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The bracelet Lily would like to buy costs $5 less than 5 times the amount she has saved . The bracelet costs $30. How much money

pochemuha

Lily has saved $ 7

<em><u>Solution:</u></em>

Given that bracelet costs $30

The bracelet Lily would like to buy costs $5 less than 5 times the amount she has saved

Cost of bracelet = $ 30

From given statement,

Cost of bracelet = 5 times the amount she has saved - 5

Let "x" be the amount saved by lily

Cost of bracelet = 5 times x - 5

Here "times" represents multiplication

30 = 5(x) - 5

30 = 5x - 5

30 + 5 = 5x

5x = 35

On dividing 35 by 5 we get 7

x = 7

Thus Lily saved $ 7

3 0

3 years ago

sampling method: assume that the population consists of all students currently in your statistics class. describe how to obtain

Naddik [55]

To obtain the sample, one can choose the names of 6 students out of a hat from the students in the class using random sampling.

<h3>What is random sampling?</h3>

It should be noted that a simple random sample is a subset of a statistical population where each member of the subset has an equal probability of being chosen.

Systematic sampling is when the sample members from a larger population are selected based on a fixed, periodic interval. If you want to select a random group of 6 students from a population of about 60 using systematic sampling, every 10th person on the list is selected.

Learn more about sampling on:

brainly.com/question/17831271

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3 years ago