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Tanzania [10]
3 years ago
13

Convert 5 miles to meters round to the nearest meter

Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

8047

Step-by-step explanation:

Five miles is equivalent to 8046.72

5 miles = 8046.72

Look at the decimal number and notice that its closer to 100 than 0

So 8046.72 is rounded to 8047

Hope this helps <3

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A company offered one half of its employees a bonus if the production of light bulbs increased by 20%. The other half of the emp
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4 = 3x -x-4<br> I need steps to how to do this​
vesna_86 [32]

Step-by-step explanation:

so first you combine like terms , 3x-x-4=4 turns into 4x-4=4 then u add 4 to both sides [inverse operations]

4x-4=4

+4 +4

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4x= 8

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4. 4

×=2

then u use inverse operations. agian and divide 4 into 8 and you get 2 !! x = 2

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3 years ago
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3 years ago
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if PQ || RS and the slope of PQ= x-1/4 and the slope of RS is 3/8 then find the value of x justify algebraically and numerically
Artemon [7]

The value of x is 5/8.

<u>Step-by-step explanation</u>:

Given,

  • The lines PQ and RS are parallel to each other.
  • slope of PQ= x-1/4
  • slope of RS = 3/8

The slopes of parallel lines are equal.

slope of PQ = slope of RS

⇒ x-1/4 = 3/8

⇒ (4x-1)/4 = 3/8

⇒ 8(4x-1) = 4(3)

⇒ 32x-8 = 12

⇒ 32x = 20

x = 20/32

x = 5/8

5 0
3 years ago
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
ivanzaharov [21]

Answer:

1508527.582 cm³/min

Step-by-step explanation:

The net rate of flow dV/dt = flow rate in - flow rate out

Let flow rate in = k. Since flow rate out = 6800 cm³/min,

dV/dt = k - 6800

Now, the volume of a cone V = πr²h/3 where r = radius of cone and h = height of cone

dV/dt = d(πr²h/3)/dt = (πr²dh/dt)/3 + 2πrhdr/dt (since dr/dt is not given we assume it is zero)

So, dV/dt = (πr²dh/dt)/3

Let h = height of tank = 12 m, r = radius of tank = diameter/2 = 3/2 = 1.5 m, h' = height when water level is rising at a rate of 21 cm/min = 3.5 m and r' = radius when water level is rising at a rate of 21 cm/min

Now, by similar triangles, h/r = h'/r'

r' = h'r/h = 3.5 m × 1.5 m/12 m = 5.25 m²/12 m = 2.625 m = 262.5 cm

Since the rate at which the water level is rising is dh/dt = 21 cm/min, and the radius at that point is r' = 262.5 cm.

The net rate of increase of water is dV/dt = (πr'²dh/dt)/3

dV/dt = (π(262.5 cm)² × 21 cm/min)/3

dV/dt = (π(68906.25 cm²) × 21 cm/min)/3

dV/dt = 1447031.25π/3 cm³

dV/dt = 4545982.745/3 cm³

dV/dt = 1515327.582 cm³/min

Since dV/dt = k - 6800 cm³/min

k = dV/dt - 6800 cm³/min

k = 1515327.582 cm³/min - 6800 cm³/min

k = 1508527.582 cm³/min

So, the rate at which water is pumped in is 1508527.582 cm³/min

5 0
3 years ago
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