Question

consider the following quadratic function f(x)= -2x^2+12x+32=0 select all the statements that are true for the function

Answer 1

Answer:

The answer to your question is

a) 400

b) The function has two real solutions (-2 and 8)

Step-by-step explanation:

Process

1.- Discriminant = b² - 4ac

                         = 12² -4(-2)(32)

                         = 144 + 256

                        = 400

2.- Solutions (using the general formula)

                   x = $\frac{- b +/- \sqrt{b^{2}- 4ac}}{2a}$

                   x = $\frac{- 12 +/- \sqrt{400}}{2(-2)}$

                   x = $\frac{-12 +/- 20}{2(-2)}$

   x₁ = $\frac{-12 + 20}{2(-2)} = \frac{-12 + 20}{-4} = \frac{-8}{4} = - 2$

   x₂ = $\frac{- 12 - 20}{- 4} = \frac{-32}{- 4} = 8$

This function has two real solutions (-2, 8)