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2 years ago

In 2/3 of a hour, workers had installed 2/5 of a foor. At the rate,what fraction of the flooring is finished after 1 hour?

1 answer:

4 0

3/5 or 60%.

2/3 hour is 40 minutes, so 1/3 is 20 minutes.

40 minutes have passed and 2/5 of the progress on the floor is complete. In 20 minutes, 1/5 of the work is complete. Add 20 minutes to 40 minutes to get 60 minutes, or an hour.
Because of this, we need to add the progress of 20 minutes and 40 minutes. 1/5+2/5=3/5.

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Assume the random variable x is normally distributed with mean u = 90 and standard deviation o=5. Find the indicated probability

Setler79 [48]

<u>Given</u>:

Let the random variable x is normally distributed with mean $\mu=90$ and $\sigma=5$

We need to determine the probability of $P(X$

<u>Probability of </u> $P(X$ <u>:</u>

The formula to determine the value of $P(X$ is given by

$Z=\frac{X-\mu}{\sigma}$

Thus, we have;

$P(X$

Simplifying, we get;

$P(X$

Using the normal distribution table, the value of -2 is given by 0.0228

$P(X$

Thus, the value of $P(X$ is 0.0228

6 0

2 years ago

An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh

natima [27]

Answer:

Speed of the plane in still air: $779\; {\rm km \cdot h^{-1}}$ .

Windspeed: $100\; {\rm km \cdot h^{-1}}$ .

Step-by-step explanation:

Assume that $x\; {\rm km \cdot h^{-1}}$ is the speed of the plane in still air, and that $y\; {\rm km \cdot h^{-1}}$ is the speed of the wind.

When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be $(x - y)\; {\rm km \cdot h^{-1}}$ .
When this plane is travelling in the same direction as the wind, the ground speed of this plane would be $(x + y)\; {\rm km \cdot h^{-1}}$ .

The question states that when going against the wind ( $v = (x - y)\; {\rm km \cdot h^{-1}}$ ,) the plane travels $6111\; {\rm km}$ in $9\; {\rm h}$ . Hence, $9\, (x - y) = 6111$ .

Similarly, since the plane travels $7911\; {\rm km}$ in $9\; {\rm h}$ when travelling in the same direction as the wind ( $v = (x + y)\; {\rm km \cdot h^{-1}}$ ,) $9\, (x + y) = 7911$ .

Add the two equations to eliminate $y$ . Subtract the second equation from the first to eliminate $x$ . Solve this system of equations for $x$ and $y$ : $x = 779$ and $y = 100$ .

Hence, the speed of this plane in still air would be $779\; {\rm km \cdot h^{-1}}$ , whereas the speed of the wind would be $100\; {\rm km \cdot h^{-1}}$ .

3 0

1 year ago

Solve this: k/3 = -4

Veseljchak [2.6K]

Step-by-step explanation:

k/3= -4
k= -4×3
k= -12

<h2>stay safe healthy and happy.</h2>

6 0

2 years ago

Read 2 more answers

The image of the point (6, -9) under a translation is (11,-4). Find the coordinates

yaroslaw [1]

Answer:

( - 6 , - 1 )

Step-by-step explanation:

Let's find the rule of that transformation:

1 + = 4 ⇒ = 3

9 + = 10 ⇒ = 1

Thus, the rule of given transformation is ( x + 3 , y + 1 )

So, the image of the point ( - 9 , - 2 ) is

( - 9 + 3 , - 2 + 1 ) = ( - 6 , - 1 )

3 0

2 years ago

Read 2 more answers

Write a multiplication equation using one whole number and one fraction that have a product of 18/8

Digiron [165]

Answer:

whole number = 8

fraction = 1/8

1/8 * 18 = 18/8

Step-by-step explanation:

fraction times a whole number = 18/8

1/8 * 18 = 18/8

6 0

2 years ago