Answer:
Both are similar by SAS similarity.
This SAS similarity is equivalent to the congruence.
Step-by-step explanation:
Step 1:
To prove that ACB and HIG as similar triangles.
We have to look upon the corresponding sides.
SAS= Side angle sides , there the angle must be in between two sides.
ACB = HIG
Lets work on the corresponding sides.
IG/AC = IH/AC
= 
Reducing each to lowest form, we divide numerator and denominator by 3 for the 1st fraction and by 4 for the 2nd fraction.
We have
=
Both sides are equal.
So its proved that both are similar with SAS similarity theorem.
Answer:
A,B, and C
Step-by-step explanation:
All of the answers are correct besides D, none of the above
Answer:
(-138) is the answer.
Step-by-step explanation:
Perfect square numbers between 15 and 25 inclusive are 16 and 25.
Sum of perfect square numbers 16 and 25 = 16 + 25 = 41
Sum of the remaining numbers between 15 and 25 inclusive means sum of the numbers from 17 to 24 plus 15.
Since sum of an arithmetic progression is defined by the expression
![S_{n}=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where n = number of terms
a = first term of the sequence
d = common difference
![S_{8}=\frac{8}{2} [2\times 17+(8-1)\times 1]](https://tex.z-dn.net/?f=S_%7B8%7D%3D%5Cfrac%7B8%7D%7B2%7D%20%5B2%5Ctimes%2017%2B%288-1%29%5Ctimes%201%5D)
= 4(34 + 7)
= 164
Sum of 15 + 
= 15 + 164 = 179
Now the difference between 41 and sum of perfect squares between 15 and 25 inclusive = 
= -138
Therefore, answer is (-138).
The second choice is the answer
2/11
there’s 2 R’s and 11 total so
possible outcomes/ overall outcomes
