You don't list the "sums listed below" but I can still help you.
There are 6 ways to get a sum of 7 using a pair of dice:
1+6
6+1 You might be asking why 2+5 isn't the same as 5+2
2+5 Imagine the dice are different colors. Is a red 2 and green 5 the
5+2 same as a green 2 and red 5? (No, it's not)
3+4
4+3
You need two numbers that also provide 6 ways to win. One pair that would work is 11 and 9 There are two ways to make 11 (5+6) and (6+5) and there are four ways to make 9 (3+6), (6+3) (4+5) and (5+4) - that's a total of six ways. So to balance your friend's 7 - you could go for sums of 11's and 9's. Check the choices you were given and find the numbers (it could be three numbers like 2,3, and 12) that give you 6 ways to win.
Here are the numbers and their ways
Sum of the dice Ways to get it
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
Answer:
x = 4
Step-by-step explanation:
10 = -1/4 x + 11
10 - 11 = -1/4 x
-1 = - 1/4 x
x = 4
There are 4 even numbers in your sample space - 2,10,30, and 36 out of 7 total numbers.
P(even) = 4/7.
Answer:
1/8 of the budget was left for other expenses.
Step-by-step explanation:
1/4 of the budget - buildings and maintenance.
Administrative personnel : 1/4 + 1/8 = 2/8 + 1/8 = 3/8 of the budget.
Therefore:
3/8 of the budget - administrative personnel.
Public safety : 3/8 - 1/8 = 2/8 = 1/4 of the budget.
For other expenses :
1 - ( 1/4 + 3/8 + 1/4 ) = 1 - ( 2/8 + 3/8 + 2/8 ) 1 - 7/8 = 1/8
Finally, 1/8 of the total budget was for the other expenses.
Y = total costs to get the berries
x = pounds of berries.
bearing in mind that the $5 is just to get in, so is only paid once, whilst the pounds of berry will vary.
