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masya89 [10]
3 years ago
5

PLEASE HELP FAST!!

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

x = 4

Step-by-step explanation:

10 = -1/4 x + 11

10 - 11 = -1/4 x

-1 = - 1/4 x

x = 4

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What is the solution set to the inequality 7z+5>47
Vsevolod [243]

Answer:

z>6

<h2>Step-by-step explanation:</h2>

7z+5>47

Remove the 5:

7z+5-5>47-5\\7z>42

Divide by 7 to get z by itself:

\frac{7z}{7} >\frac{42}{7} \\z>6

5 0
3 years ago
Find the simple interest.
Mademuasel [1]
We need to compute the exact number of days of the loan.

Given:
Loan: 1,870
rate: 11%
term: Oct. 5 to Jan 16.

Oct 5-Oct 31: 26 days
Nov: 30 days
Dec: 31 days
Jan 16: 16 days.
total number of days: 103 days.

Interest = Principal * rate * term
Interest = 1870 * 0.11 * 103/365
Interest = 58.05

Given:
Promissory note $5,380
rate 6.2%
term: July 15 to Dec. 28

July 15 - 31 = 16 days
August: 31 days
September: 30 days
October: 31 days:
November: 30 days
December: 28 days
Total number of days is 166 days

Interest = Principal * rate * term
Interest = 5,380 * 0.062 * 166/365
Interest = 151.70
8 0
3 years ago
Rema spent 6 days reading her book, completing the same fraction of the book each day, if she read a total of 8/9 of her book af
AnnZ [28]
(8/9) / 6 =
8/9 * 1/6 =
8/54 which reduces to 4/27 of the book each day <===
7 0
3 years ago
It takes Earth about 365 days to orbit the Sun. It takes Uranus about 85 times as long. Write a numerical expression to describe
steposvetlana [31]
U=days of Uranus Orbit
365x85=U
3 0
3 years ago
Od<br> 2<br> (<br> 2 7 1-3<br> 1 3 1-2<br> 6:1-6<br> b =<br> d =<br> IDONE
Lena [83]

Answer:

a = \boxed{1},\: b=\boxed{0}\\\\c=\boxed{0},\: d=\boxed{1}

Step-by-step explanation:

  • \begin{bmatrix} 2 & 7\\\\1 & 3\end{bmatrix}\:\begin{bmatrix} -3 & 7\\\\1 & -2\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Multiply both the matrices on left side, we find:

  • \begin{bmatrix} 2(-3)+7(1) & 2(7)+7(-2)\\\\1(-3)+3(1) & 1(7)+3(-2)\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} -6+7 & 14-14\\\\-3+3 & 7-6\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • \rightarrow\begin{bmatrix} 1 & 0\\\\0 & 1\end{bmatrix}=\begin{bmatrix} a & b\\\\c & d\end{bmatrix}

  • Comparing the corresponding elements of both the matrices on both sides, we find:

  • a = \boxed{1},\: b=\boxed{0},\:c=\boxed{0},\: d=\boxed{1}
7 0
2 years ago
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