Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
Hello, hope this will help:)
Answer:
11.59x² -7.66x + 9.85
Step-by-step explanation:
3.63x² - 4.54x + 7.96x² +9.85 -3.12x
11.59x² -7.66x + 9.85
Both sides equal each other. Do you want to know how?
√(4 + 16 + 16√3 + 12) = 4√(2 + √3)
Surd Rule: Numbers with the same surd can be added together. Therefore, all whole integers can be added together.
√(4 + 16 + 16√3 + 12)
√((4 + 16 + 12 )+ 16√3 ) =
√(32 + 16√3)
Simplify by Factorising the common factor - 16
√(32 + 16√3) ÷ 16
√(16 (2 + √3))
Square root 16. This is because it is a not a surd because it is not in it's simplest form.
√16 = 4
√4 (2 + √3)
