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Grace [21]
3 years ago
9

On a shopping trip, Steve spent $3 on a bus ticket, $12 on a game,

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0
Well, first let’s add up how much Steve spent in total. So, 3+12+6 which equals 21. Steve had $25 left so add the leftover to the amount spent which would be 25+21=46
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If three-eights of a pound of candy was shared equally among the 3 people, what fraction of a pound did each person receive?
REY [17]
Hola!

3/8 ÷ 3 = 1/8

Each person would recieve 1/8 a pound of candy.

Hope this helps!

~DL
3 0
3 years ago
What is the solution to this inequality x-7<1
Nina [5.8K]
X−7<1

Add 7 to both sides.

x−7+7<1+7

x<8

To plot this on a number line, put a circle around 8 and a line going to the left with an arrow at the end.
8 0
3 years ago
Read 2 more answers
Can I see how long division works on these? pls no sketchy links
alexandr1967 [171]

Answer:

Step-by-step explanation:

11) First write in decreasing exponential terms and fill in blanks with zeros.

Our goal is to eliminate all term in the dividend by subtraction

          ________________

2v - 2 |  2v³ - 16v² + 0v + 13

we see that 2v needs to be multiplied by 1v² to eliminate the first term

          <u>              v²                </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v²

multiply your estimate by your divisor and subtract from the dividend.

bring down the next term and repeat.

          <u>              v²    -7v       </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v

repeat again

<u />

          <u>              v²  -  7v  -  7 </u>

2v - 2 |  2v³ - 16v² + 0v + 13

         <u>- (2v³ - 2v²)</u>

              0  - 14v² + 0v

                 <u>-(-14v² + 14v)</u>

                             - 14v + 13

                            <u>-(-14v + 14)</u>

                                          -1

and remainder gets put over the divisor and appended

v²  -  7v  -  7 - 1/(2v - 2)

13) Same process

          <u>                                      </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>              8a²                 </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

          <u>              8a² -    4a     </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                   -(-<u>20a² -   4a)</u>

                                -35a - 5

          <u>              8a² -    4a  - 7  </u>

5a + 1 |  40a³ - 12a² - 39a - 5

          <u>-(40a³ + 8a²)</u>

                     -20a² - 39a

                    -(<u>20a² -   4a)</u>

                                -35a - 5

                              -<u>(-35a - 7)</u>

                                           2

8a² - 4a - 7 + 2/(5a + 1)

5 0
3 years ago
Find the vertex f(x)=2(x+1)(x-5)
Eddi Din [679]
I hope i’m correct. Hope this helps!

3 0
3 years ago
Are Triangles similar?
kvasek [131]

Given:

A figure of triangles.

To find:

Whether the triangles SPT and triangle QPR are similar.

Solution:

In triangle SPT and triangle QPR,

\angle PST\cong \angle PQR           (Given)

\angle SPT\cong \angle QPR           (Common angle)

In triangles SPT and triangle QPR, two corresponding angles are congruent. So, by AA property of similarity both triangles are similar.

\angle SPT\sim \angle QPR

Therefore, yes, the triangle SPT and triangle QPR similar. Option A is correct.

4 0
3 years ago
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