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Ilya [14]
3 years ago
5

If you want to put a 4x8 piece of plywood through a 3-foot square opening in your ceiling by turning it diagonally, is the openi

ng big enough? Use 45-45-90 triangle since it is a square
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
6 0

The first step is to calculate the length of the diagonal of the square opening.

The length of a diagonal of square = \sqrt{2} * side

Given side = 3 feet

Length of the square hole = \sqrt{2} *3 = 4.24 feet

since the diagonal is 4.24 feet and the shorter side of the plywood piece is only 4 feet, we can slide it through the square hole diagonally

Answer is YES since the diagonal 4.24 feet is greater than the shorter side of the plywood piece *4 feet

Black_prince [1.1K]3 years ago
3 0
THe diagonal of the 3*3 square = 3* sqrt2 = 4.24 feet   so the answer is Yes.
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In the graph below, Point A represents Owen's house, Point B represents David's house and Point C represents the school. Who liv
ycow [4]

Answer:

• David

,

• 4 miles

Explanation:

In the graph:

The given locations are:

• Owen's House, A(11,3)

,

• David's House, B(15,13)

,

• School, C(3,18)

We determine both Owen's and David's distance from the school using the distance formula.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Owen's distance from school (AC)

\begin{gathered} AC=\sqrt[]{(3-11)^2+(18-3)^2} \\ =\sqrt[]{(-8)^2+(15)^2} \\ =\sqrt[]{64+225} \\ =\sqrt[]{289} \\ AC=17\text{ miles} \end{gathered}

David's distance from school (BC)

\begin{gathered} BC=\sqrt[]{(3-15)^2+(18-13)^2} \\ =\sqrt[]{(-12)^2+(5)^2} \\ =\sqrt[]{144+25} \\ =\sqrt[]{169} \\ BC=13\text{ miles} \end{gathered}

We see from the calculations that David lives closer to the school, and by 4 miles.

The graph below is attached for further understanding:

5 0
1 year ago
Arranging like terms; solve the linear system using eliminationlly - 3x = 18- 3x = -16y + 33
DENIUS [597]

Solution

For this case we can do the following:

11y - 3x = 18

16y -3x = 33

We can multiply the first equation by -1 and we got:

-11y +3x =-18

16y -3x = 33

_______________

16y -11y = 33-18

5y = 15

y= 15/5 = 3

And then solving for x we got

x = -(18 -11*3)/ 3= -15/3 = 5

8 0
1 year ago
Find the length of the altitude to the hypotenuse. Round the answer to the nearest tenth, if needed.
SVEN [57.7K]
To solve this, it might be easier to draw it out (see the picture below). I split it into two triangles and used trig functions to find the altitude. I used the big triangle to find theta, and the used theta to find the side of the altitude. *remember that sine= opposite/hypotenuse*

8 0
3 years ago
Solve each word problem using a system of equations. Use substitution or elimination.
nasty-shy [4]

Answer:

Step-by-step explanation:

x + 3y = 24.....multiply by -1

5x + 3y = 36

------------------

-x - 3y = -24 (result of multiplying by -1)

5x + 3y = 36

------------------add

4x = 12

x = 12/4

x = 3 <=======

x + 3y = 24

3 + 3y = 24

3y = 24 - 3

3y = 21

y = 21/3

y = 7 <========

4 0
3 years ago
Anyone please could help
Shalnov [3]
The answer would be c.127
5 0
3 years ago
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