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3 years ago

Oliver owns a paper mill. It has machines that use wood pulp to make paper. Which is an intermediate good?

Mathematics

2 answers:

Kay [80]3 years ago

7 0

Wood pulp i not entirely sure i think you need to word the question better

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prisoha [69]3 years ago

4 0

Answer: Second option is correct.

Step-by-step explanation:

Since we have given that

Oliver owns a paper mill. It has machines that use wood pulp to make paper.

Since they use wood pulp that means it is an "Intermediate goods " to make paper that means it is a "Final good".

Intermediate goods means that goods which are used as raw material for resale or for reinvestment.

So, Second option is correct.

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1 year ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

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Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

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I gotta go so I'll stop here, sorry.

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